[Bored chemist]

Apsidal_precession

I think he's talking about apsidal precession, but he seems to think it has something to do with supermoons.

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Ss) / (Vl / Sz) = 0.000058 / 0.0018 = 0.032
----------------
Where Vz - Orbital angular velocity of the Earth - 0.00011 r / h.
Ss - The distance from the Sun to the Earth is 150,000,000 km.
--------------
Where Vl - Orbital angular velocity of the moon - 0,0013 r / h.
Sz - Distance from the Earth to the Moon 384 000 km.
The eccentricity of the orbit of the moon varies, from 0.026 to 0.077).

[Bored chemist]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Ss) / (Vl / Sz) = 0.000058 / 0.0018 = 0.032
----------------
Where Vz - Orbital velocity of the Earth - 0,00011 r / h.
Ss - The distance from the Sun to the Earth is 150,000,000 km.
--------------
Where Vl - Orbital velocity of the Moon - 0.0013 r / h.
Sz - Distance from Earth to Moon - 384,000 km.
The eccentricity of the orbit of the moon varies, from 0.026 to 0.077).

So, it's still worng.

Quote from: Bored chemist on 29/06/2020 22:39:46
Now, can you get back to the point?

Quote from: Bored chemist on 28/06/2020 20:12:45
Now, please answer the question.


Quote from: Bored chemist on Yesterday at 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.

[Yusup Hizirov (OP)]

Does it work for Phobos?

Vz = 86,430 km/h
Ss = 227,939,200 km
Vl = 7,696.8 km/h
Sz = 9,376 km/h

E = (86,430/227,939,200)/(7,696.8/9,376)
E = (3.7918 x 10^-4)/(0.821)
E = 4.6185 x 10^-4

The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.

Check your calculations.

[Kryptid]

Check your calculations.

If you got a different answer, then post your calculations.

[Colin2B]

Does it work for Phobos?

Vz = 86,430 km/h
Ss = 227,939,200 km
Vl = 7,696.8 km/h
Sz = 9,376 km/h

E = (86,430/227,939,200)/(7,696.8/9,376)
E = (3.7918 x 10^-4)/(0.821)
E = 4.6185 x 10^-4

The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.

Check your calculations.

Please point out exactly where the error is and why it is an error. Otherwise you are in danger of being considered a troll.

[Bored chemist]

Otherwise you are in danger of being considered a troll.

That ship has sailed.

[Yusup Hizirov (OP)]

Does it work for Phobos?

Vz = 86,430 km/h
Ss = 227,939,200 km
Vl = 7,696.8 km/h
Sz = 9,376 km/h

E = (86,430/227,939,200)/(7,696.8/9,376)
E = (3.7918 x 10^-4)/(0.821)
E = 4.6185 x 10^-4

The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.

Check your calculations.

Please point out exactly where the error is and why it is an error. Otherwise you are in danger of being considered a troll.

Vz = 86,430 rpm
Vl = 7 696.8 rpm

[Bored chemist]

Vz = 86,430 rpm

That's  the wrong units for a velocity, and stupidly wrong because it's 2 or 3 times faster than an electric drill.
https://uk.farnell.com/dremel/4200-4-75/rotary-tool-175w-33000rpm/dp/2422656?CMP=KNC-GUK-GEN-KWL-MAN-L5Pages-New-Structure-25May2020-CatchAll&mckv=_dc|pcrid|437370423018|&gclid=CjwKCAjwrvv3BRAJEiwAhwOdM9eCk4-TYjPQZ7tV8K44E1Jn16n88G19_d53sERmukdWl3ihCpdsLhoCCxAQAvD_BwE

You need to get things right before you tell others to check their calculations.
Not that it matters.
You calculate a single value for the eccentricity of the Moon, but reality gives it a range- it varies.
So you are wrong.

[Yusup Hizirov (OP)]

The solar Coriolis effect is involved in the formation of the moon ellipse.
When the Moon revolving around the Earth in the last quarter approaches the Sun at a speed of 1 km / s, and in the first quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the moon's orbit along the Earth's orbit. Thanks to what the elliptical orbit of the Moon is formed. https://images.app.goo.gl/wmqRKPc9jzScCrB16
When the Moon is in the phase of the new moon and full moon, the Solar Coriolis effect does not affect the orbit of the Moon, because in these phases, the moon does not approach and does not move away from the sun.
The eccentricity of the orbit of the moon varies, from 0.026 to 0.077.
-------------------
The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vl / Vz = 28/365 = 0,076
----------------
Where Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.

[Bored chemist]

eccentricity of the orbit of the moon

You calculate a single value for the eccentricity of the Moon, but reality gives it a range- it varies.
So you are wrong.

Quote from: Bored chemist on 30/06/2020 15:08:04
Quote from: Bored chemist on 29/06/2020 22:39:46
Now, can you get back to the point?

Quote from: Bored chemist on 28/06/2020 20:12:45
Now, please answer the question.


Quote from: Bored chemist on Yesterday at 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.

[Kryptid]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vl / Vz = 28/365 = 0,076
----------------
Where Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.

In what units is the orbital velocity of the Moon 28 and the Earth 365? If I divide the orbital velocity of the Moon in km/s (1.022) and that of the Earth (29.78), then I get 0.0343. But that number should be the same regardless of the units. So your calculation of 0.076 is wrong if you are talking about orbital velocities.

Did you mean orbital period instead? That would make more sense, given that the Moon's orbital period is 28 days and the Earth's is 365 days. But when we try this with Phobos (0.3189 days) and Mars (686.971), we get a predicted eccentricity of 0.000464 (which is very wrong). So this equation doesn't work either.

[Bored chemist]

, we get a predicted eccentricity of 0.000464 (which is very wrong). So this equation doesn't work either.

He has provided many variations of wrong!
But not a single example of right.

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vl / Vz = 28/365 = 0,076
----------------
Where Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.

In what units is the orbital velocity of the Moon 28 and the Earth 365? If I divide the orbital velocity of the Moon in km/s (1.022) and that of the Earth (29.78), then I get 0.0343. But that number should be the same regardless of the units. So your calculation of 0.076 is wrong if you are talking about orbital velocities.

Did you mean orbital period instead? That would make more sense, given that the Moon's orbital period is 28 days and the Earth's is 365 days. But when we try this with Phobos (0.3189 days) and Mars (686.971), we get a predicted eccentricity of 0.000464 (which is very wrong). So this equation doesn't work either.

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Ss) / (Vl / Sz) = 0.0000584 / 0.001875 = 0.031
----------------
Where Vz - Orbital velocity of the Earth - 8760 r / h.
Ss - The distance from the Sun to the Earth is 150,000,000 km.
--------------
Where Vl - Orbital speed of the Moon - 720 r / h.
Sz - Distance from the Earth to the Moon 384 000 km.
************************************
The eccentricity of the Phobos orbit can be calculated by the following formula.
E ≈ (Vm / Ss) / (Vph / Sz) = 0.000093 / 0.0078 = 0.0119
----------------
Where Vm - Orbital velocity of Mars - 18696 revolution / hour.
Ss - The distance from the Sun to Mars is 200,000,000 km.
--------------
Where Vf - Phobos orbital speed - 7.4 hrpm
Sz - Distance from Mars to Phobos 9400 km.

[Kryptid]

Orbital velocity of Mars - 18696 revolution / hour.

Do you have any idea just how wrong this is?

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Sz) / (Vl / Sl) = 0.0000584 / 0.001875 = 0.031
----------------
Where Vz - Orbital velocity of the Earth - one revolution in 8760 hours.
Sz - The distance from the Sun to the Earth is 150,000,000 km.
--------------
Where Vl - Orbital velocity of the Moon - one revolution in 720 hours.
Sl - Distance from the Earth to the Moon 384 000 km.
************************************
The eccentricity of the Phobos orbit can be calculated by the following formula.
E ≈ (Vm / Sm) / (Vf / Sf) = 0.000081 / 0.00078 = 0.0103
----------------
Where Vm - Orbital velocity of Mars - one revolution in 18696 hours.
Sm - The distance from the Sun to Mars is 230,000,000 km.
--------------
Where Vf - Phobos orbital speed - one revolution in 7.4 hours.
Sf - Distance from Mars to Phobos 9400 km.

[Kryptid]

Those still aren't the correct eccentricity values.

[Bored chemist]

Those still aren't the correct eccentricity values.

He has provided many variations of wrong!
But not a single example of right.

Quote from: Bored chemist on 02/07/2020 13:34:17
Quote from: Bored chemist on 30/06/2020 15:08:04
Quote from: Bored chemist on 29/06/2020 22:39:46
Now, can you get back to the point?

Quote from: Bored chemist on 28/06/2020 20:12:45
Now, please answer the question.


Quote from: Bored chemist on Yesterday at 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.

[Bored chemist]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Ss) / (Vl / Sz) = 0.0000584 / 0.001875 = 0.031

Liar.

[Bored chemist]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vl / Vz = 28/365 = 0,076

Liar