0 Members and 1 Guest are viewing this topic.

Come on guys, why so serious So many views and only two opinions?Jano

For a third opinion, see: https://www.thenakedscientists.com/forum/index.php?topic=79146.msg598377#msg598377

Quote from: Jaaanosik on 05/04/2020 00:59:23Come on guys, why so serious So many views and only two opinions?JanoOpinions can't change the laws of physics.

Kryptid,the solution does not change the laws of physics.It strives in them!

Quote from: Jaaanosik on 05/04/2020 03:52:57Kryptid,the solution does not change the laws of physics.It strives in them!So how do you propose to create momentum out of nowhere without violating conservation of momentum?

What do you mean out of nowhere?I said there would be an energy source and it would do something inside the ship.No ejection of a mass out is allowed though,Jano

Energy is not momentum.

But it can be used to generate momentum,Jano

Quote from: Kryptid on 05/04/2020 04:12:39Energy is not momentum.But it can be used to generate momentum,Jano

Quote from: Jaaanosik on 05/04/2020 04:14:34Quote from: Kryptid on 05/04/2020 04:12:39Energy is not momentum.But it can be used to generate momentum,JanoNot net momentum. Momentum is a vector, it has both magnitude and direction. You can take a certain store of potential energy and convert it to kinetic energy, Energy is a scalar, so all you have to worry about is conserving magnitude in terms of conserving energy. So a compressed spring will have a stored energy of E = 1/2kx^2, where k is the spring constant and x the amount the spring was compressed. This can be converted into kinetic energy as mv^2/2. meaning a mass m moving at velocity v. Energy is conserved. Momentum also in conserved. Momentum is mv. Now in the energy equation, v is squared, thus the direction of the velocity, which is itself a vector, doesn't matter. v^2 and (-v)^2 produce the same answer. However with momentum it isn't, thus mv is not the same as m(-v), and, in fact, they are opposites.Like energy, momentum is conserved. Our mass and compressed spring start with no velocity, so the total momentum is m(0) = 0. After the spring has converted its stored energy into kinetic energy of mass m, the total momentum must still be 0. The only way to do this to divide m in two where m1+m2 = m and then m1v1 + m2v2 = 0 Since m cannot be negative, either v1 or v2 must be negative, Meaning m1 and m2 must be sent in opposite directions. The only way to get m1 moving to the right at v1, is to have m2 moving to the left at v2 such that the sum of the momenta add up to zero.

Quote from: Janus on 05/04/2020 16:52:56Quote from: Jaaanosik on 05/04/2020 04:14:34Quote from: Kryptid on 05/04/2020 04:12:39Energy is not momentum.But it can be used to generate momentum,JanoNot net momentum. Momentum is a vector, it has both magnitude and direction. You can take a certain store of potential energy and convert it to kinetic energy, Energy is a scalar, so all you have to worry about is conserving magnitude in terms of conserving energy. So a compressed spring will have a stored energy of E = 1/2kx^2, where k is the spring constant and x the amount the spring was compressed. This can be converted into kinetic energy as mv^2/2. meaning a mass m moving at velocity v. Energy is conserved. Momentum also in conserved. Momentum is mv. Now in the energy equation, v is squared, thus the direction of the velocity, which is itself a vector, doesn't matter. v^2 and (-v)^2 produce the same answer. However with momentum it isn't, thus mv is not the same as m(-v), and, in fact, they are opposites.Like energy, momentum is conserved. Our mass and compressed spring start with no velocity, so the total momentum is m(0) = 0. After the spring has converted its stored energy into kinetic energy of mass m, the total momentum must still be 0. The only way to do this to divide m in two where m1+m2 = m and then m1v1 + m2v2 = 0 Since m cannot be negative, either v1 or v2 must be negative, Meaning m1 and m2 must be sent in opposite directions. The only way to get m1 moving to the right at v1, is to have m2 moving to the left at v2 such that the sum of the momenta add up to zero. Janus,agreed, this is all good.Having said that I am not going to break the physics laws, I am going to bend them, literally.Before going further a statement/disclaimer:If this is going to be proven as a viable propulsion system I claim prior art/design and it is my wish this design belongs to public domain/all human kind.JanoLet us discuss.Is this going to work?

Quote from: evan_au on 05/04/2020 01:56:53For a third opinion, see: https://www.thenakedscientists.com/forum/index.php?topic=79146.msg598377#msg598377Yes,I've seen that. That's the reason I said no interaction with outside fields.Just something happening inside the ship itself,Jano