[Bored chemist]

Lower limit on missing energy: 1.7*10^(-119) J.

So, your idea is deliberately untestable.
Why pretend that it's science?

[talanum1 (OP)]

So, your idea is deliberately untestable.
Why pretend that it's science?

L⁰ is detectable using changes in a Strong Force-field.

[Kartazion]

L⁰ is detectable using changes in a Strong Force-field.

What is L? and what does mean "changes in a Strong Force"? QuantumChromodynamics or decay?

[talanum1 (OP)]

What is L? and what does mean "changes in a Strong Force"? QuantumChromodynamics or decay?

L⁰ is a new particle I predicted. Quantum Chromodynamics.

[Kartazion]

L⁰ is a new particle I predicted. Quantum Chromodynamics.

Then if L is complementary to the operation of the QCD, is it a boson or a fermion? And how is the representation of it in the Feynman diagram? What path between which particles?

[talanum1 (OP)]

Then if L is complementary to the operation of the QCD, is it a boson or a fermion? And how is the representation of it in the Feynman diagram? What path between which particles?

It is neither a Fermion nor a Boson: it doesn't have spin. It has no representation on a Feynman diagram yet. It is on a path from the Pi-minus out of the system. It is however required by Structure Conservation (see paper).

[Kartazion]

It is neither a Fermion nor a Boson: it doesn't have spin. It has no representation on a Feynman diagram yet. ...

Is the neutral L an elementary or composite particle?

... It is on a path from the Pi-minus out of the system. ...

Out of the system? There would then be another system with another quantity of energy?

Below is an example path; Where is your neutral L? It is difficult to have another system than ours.


A proton emanating from a cosmic ray strikes an atmospheric molecule. A π+ pion appears here which decays into a μ+ muon and a νμ muon neutrino. The muon μ+ in turn produces an electron neutrino νe accompanied by a muonic antineutrino. https://journals.openedition.org/bibnum/811?lang=en

[Kryptid]

Lower limit on missing energy: 1.7*10^(-119) J.

I'm not sure that an energy that small can even be detected.

[talanum1 (OP)]

Is the neutral L an elementary or composite particle?

It is a composite particle.

Out of the system? There would then be another system with another quantity of energy?

I mean it leaves the vertex where the decay happened.

Below is an example path; Where is your neutral L? It is difficult to have another system than ours.

There would just be an anti-L⁰. It will start at the vertex where the pi-plus decayed.

[Kartazion]

It is a composite particle.

Composed of which and which particle?

I mean it leaves the vertex where the decay happened.

Where does it leave its energy? The energy has to go somewhere.

[edit] You said above that your particle was included in the QCD mechanism. But you can't have the same disintegrated particle. But what you are saying is that your particle is created after the decay.

[Kartazion]

It is neither a Fermion nor a Boson: ...

Just to know. How much dimension use your system for this particle? And can you complete the rest of this word: Any**

[Bored chemist]

So, your idea is deliberately untestable.
Why pretend that it's science?

L⁰ is detectable using changes in a Strong Force-field.

How?

[talanum1 (OP)]

I'm not sure that an energy that small can even be detected.

When using other another computation method, and with the assumption that mass is encoded by millions of space points, I recomputed the lower limit as: 5.79 eV.

How?

Set up a Strong Force field (by arranging nuclei in a lattice) and detectors of the field, then send a pi-minus close to the field and observe the field.

How much dimension use your system for this particle? And can you complete the rest of this word: Any**

The particle is 2 dimensional, but it lives in 3 dimensions. Anyon?

Composed of which and which particle?

Composite of properties of an anti-up and down quark.

Where does it leave its energy? The energy has to go somewhere.

It goes on infinitely far. I can't see a method for it being absorbed.

But you can't have the same disintegrated particle.

I don't know what you mean by this.

But what you are saying is that your particle is created after the decay.

Yes.

[Kartazion]

The particle is 2 dimensional, but it lives in 3 dimensions. Anyon?

Two dimensions are possible. Three dimensions include Bose-Einstein or Fermi-Dirac statistics, either boson or fermion. Anyon is the correct answer. Well done.

Composite of properties of an anti-up and down quark.

Your particle is therefore a meson. I inform you that your particle is already cataloged under the reference of Rho meson.

quark ūd    symbol ρ–    spin 1    mass 770 MeV/c²

But you can't have the same disintegrated particle.

I don't know what you mean by this.

But what you are saying is that your particle is created after the decay.

Yes.

This is because you talked about QCD rather than deacy:

What is L? and what does mean "changes in a Strong Force"? QuantumChromodynamics or decay?

L⁰ is a new particle I predicted. Quantum Chromodynamics.

[talanum1 (OP)]

L⁰ is not the same as ρ^-. It is only made of some properties of anti-ud.

[Kartazion]

L⁰ is not the same as ρ^-. It is only made of some properties of anti-ud.

You want to talk about gluon there...

[talanum1 (OP)]

"Ice Cube" can measure neutrino energies. See:

at timestamp: 16:14. But not accurately enough.

[Bored chemist]

"Ice Cube" can measure neutrino energies. See:

Citing a vid from someone who doesn't believe in the big bang is... an odd choice.
Anyway

" IceCube is designed to look for point sources of neutrinos in the TeV range"
from
https://en.wikipedia.org/wiki/IceCube_Neutrino_Observatory

so it's not going to help you, is it?

[Kryptid]

When using other another computation method, and with the assumption that mass is encoded by millions of space points, I recomputed the lower limit as: 5.79 eV.

That would give it a mass greater than those of neutrinos (which have an upper limit of 0.8 eV): https://www.nature.com/articles/d41586-022-00430-x

So if an anomalous momentum change in particle decay caused by neutrinos is detectable, then evidence for your hypothetical particle should have already been found.

[talanum1 (OP)]

So if an anomalous momentum change in particle decay caused by neutrinos is detectable, then evidence for your hypothetical particle should have already been found.

Neutrinos have velocity as well, so their energy can be more than 5.79 eV.

The reference above graphs energies of GeVs and more.

L⁰ does not have mass. Although I can be mistaken. Nothing prevents it from having mass.