[Bored chemist]

Everything is correct.

no.
Not everything.
What you say is incorrect.


Do you understand that we can measure the orbital eccentricity?
We have measured it for Phobos and the real answer is 0.0151

So why are you trying to spin us some line where it's 0.000448

Don't you understand that if your calculation doesn't agree with reality, that doesn't mean that reality is mistaken?

Prove that I'm wrong, by your calculations.

You are being absurd.
It's as if you said something like this
"You can calculate the distance from London to New York by dividing the population of one by the other.
The population of new york is 8.4 million, that of london is 9.0 million, so the distance between them is 0.933 miles."

It's not just wrong, it's laughable, because it's about 3500 miles.
And then you say "Well show me your calculation for the distance to New York".

Well, it's not a calculation; it's a measurement.

People have measured the eccentricities of the orbits.
Most notably, this one for the Moon.
https://en.wikipedia.org/wiki/Lunar_Laser_Ranging_experiment
Your calculation gives the wrong answer.

[Kryptid]

Everything is correct.

Then why didn't your equation give a value of 0.0151 for Phobos' eccentricity?

Prove that I'm wrong with your formulas.

It's your formula that has been proven to be wrong. 0.0151 does not equal 0.000448. That proves that it's wrong.

[Bored chemist]

Everything is correct.

Then why didn't your equation give a value of 0.0151 for Phobos' eccentricity?

Prove that I'm wrong with your formulas.

It's your formula that has been proven to be wrong. 0.0151 does not equal 0.000448. That proves that it's wrong.

I don't think Yusup realised that eccentricities are actually real things that we have measured.
I think he thought they were some theoretical calculation.

It's not as if it's the first time he has been utterly wrong about how science works.

[Yusup Hizirov (OP)]

The solar Coriolis effect is involved in the formation of the orbits of the satellites of the planets.
When the Moon revolving around the Earth in the fourth quarter approaches the Sun at a speed of 1 km / s, and in the second quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the Moon’s orbit along the Earth’s orbit, thereby forming an ellipse of the Moon’s orbit.
When the moon is in the phase of the new moon and the full moon, the solar Coriolis effect does not affect the orbit of the moon, because in these phases the moon does not approach and does not move away from the sun.
The eccentricity of the lunar orbit varies from 0.044 to 0.072.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity

The eccentricity of the orbit of the moon can be calculated by the following formula. E ≈ Vl / Vz.
Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.
The orbital speed of the moon is one revolution in 720 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 720/8760 ≈ 0,082
--------------
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / Vz
Where Vi is the satellite orbital velocity.
Vz - Orbital velocity of the Earth.
The satellite orbital speed is one revolution in 24 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 24/8760 ≈ 0.0027
--------------
The eccentricity of the Phobos orbit can be calculated by the following formula. E ≈ Vf / Vm
Where Vf - Orbital velocity of Phobos.
Vm - Orbital velocity of Mars.
The orbital speed of Phobos is one revolution in 7.4 hours.
The orbital speed of Mars is one revolution in 16488 hours.
E ≈ 7.4 / 16488 ≈ 0.000448
--------------
The eccentricity of the Deimos orbit can be calculated by the following formula. E ≈ Vd / Vm
Where Vd is the orbital velocity of Deimos.
Vm - Orbital velocity of Mars.
Deimos's orbital speed is one revolution in 30 hours.
The orbital speed of Mars is one revolution in 16488 hours.
30/16488 ≈ 0.0018
---------------
The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity
The assertion that the elliptical orbit of the planets is formed as a result of the disturbance of the planets contradicts reality. Venus moves almost in a circular orbit.
The reason for the formation of the ellipse of the planets is in the task of three bodies. http://www.sat.belastro.net/glava2/glava2.php#p1.2.c

Based on the formula E ≈ Vl / Vz
can be adjusted, the distance from the Sun to the Earth and the orbital velocity of the Earth.

[Bored chemist]

Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.
The orbital speed of the moon is one revolution in 720 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 720/8760 ≈ 0,082

Wrong.
Because the correct answer, as measured in reality, is 0.0549

The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / Vz
Where Vi is the satellite orbital velocity.
Vz - Orbital velocity of the Earth.
The satellite orbital speed is one revolution in 24 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 24/8760 ≈ 0.0027

Wrong, because the eccentricity of geostationary satellites is variable. The range is from less than .0001 to 0.008.
Your formula says it's sonstant, so your formula is wrong.

The eccentricity of the Phobos orbit can be calculated by the following formula. E ≈ Vf / Vm
Where Vf - Orbital velocity of Phobos.
Vm - Orbital velocity of Mars.
The orbital speed of Phobos is one revolution in 7.4 hours.
The orbital speed of Mars is one revolution in 16488 hours.
E ≈ 7.4 / 16488 ≈ 0.000448

The real answer  0.0151

The eccentricity of the Deimos orbit can be calculated by the following formula. E ≈ Vd / Vm
Where Vd is the orbital velocity of Deimos.
Vm - Orbital velocity of Mars.
Deimos's orbital speed is one revolution in 30 hours.
The orbital speed of Mars is one revolution in 16488 hours.
30/16488 ≈ 0.0018

The real value i 0.00024

The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.

THEY ARE NOT COMPILED FROM A FORMULA. THEY ARE REAL MEASURED VALUES.

You get the wrong answer in every single case.
Why are you sticking to this nonsense?

[Kryptid]

The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.

What formula is used to measure a person's height?

[Colin2B]

The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.

What formula is used to measure a person's height?

h?

[Bored chemist]

To date, the eccentricities of planetary satellites are determined by trial and error,

No.
They are measured.
For example, we know the path of the moon tor exceptional accuracy.
We know that because as I already pointed out, we are able to measure the distance to the moon very accurately.https://en.wikipedia.org/wiki/Lunar_Laser_Ranging_experiment

And, if you think about it, you will see that we know the orbits of the GPS satellites very accurately too.

So, we know what the eccentricities of the orbits are.

We don't need to calculate them.
We don't need a formula.

If someone asks you how tall you are, do you use a formula, or a ruler?
Why can't you understand that?

[Bored chemist]

because there are no formulas and methods for determining the eccentricities of orbits.

There is no formula. There is a simple way to determine the eccentricity- you measure it.
Why won't you accept that?

[The Spoon]

Interesting. Looks like the OP has removed some posts that make him look even more foolish than normal.

[Kryptid]

To date, the eccentricities of planetary satellites are determined by trial and error,

You have made some ridiculous statements in the past, but this one takes the cake. Is directly measuring something (like, say, a person's height) a matter of trial and error?

because there are no formulas and methods for determining the eccentricities of orbits.

There actually is a formula: https://en.wikipedia.org/wiki/Orbital_eccentricity#Calculation

eccentricity = (radius of apoapsis - radius of periapsis)/(radius of apoapsis + radius of periapsis)

Lunar eccentricity = (405,000 km - 362,600 km)/(405,000 km + 362,600 km)
Lunar eccentricity = 42,400 km/767,600 km
Lunar eccentricity = 0.055

For the Moon, the apoapsis and periapsis are known to very high accuracy because of the Lunar Laser Ranging experiment. It is so accurate that it has allowed us to measure that the Moon is moving away from the Earth at about 3.8 centimeters each year. That is not trial and error. So the next time you say that no such formula exists or that it is a process of trial and error, it will be a lie.

[Yusup Hizirov (OP)]

The solar Coriolis effect is involved in the formation of the orbits of the satellites of the planets.
When the Moon revolving around the Earth in the fourth quarter approaches the Sun at a speed of 1 km / s, and in the second quarter moves away from the Sun at a speed of 1 km / s, the Coriolis Solar Force stretches the Moon’s orbit along the Earth’s orbit, thereby forming an ellipse of the Moon’s orbit.
When the moon is in the phase of the new moon and the full moon, the solar Coriolis effect does not affect the orbit of the moon, because in these phases the moon does not approach and does not move away from the sun.
The eccentricity of the lunar orbit varies from 0.044 to 0.072.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity
The eccentricity of the orbit of the moon can be calculated by the following formula. E ≈ Vl / Vz.
Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.
The orbital speed of the moon is one revolution in 720 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 720/8760 ≈ 0,082
--------------
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / Vz
Where Vi is the satellite orbital velocity.
Vz - Orbital velocity of the Earth.
The satellite orbital speed is one revolution in 24 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 24/8760 ≈ 0.0027
--------------
Today, the eccentricity of planetary satellites is determined by trial and error, because, there are no formulas and methods for determining the eccentricity of orbits.
http://www.sat.belastro.net/glava2/glava2.php#p1.2.c
Based on the formula E ≈ Vl / Vz, it is possible to correct the distance from the Sun to the Earth, the orbital velocity of the Earth and the eccentricities of planetary satellites.
https://en.m.wikipedia.org/wiki/Orbital_eccentricity
The statement that the elliptical orbit of the planets, the result of the disturbance of the planets is contrary to reality, because Venus moves almost in a circular orbit.
The reason for the formation of the ellipse of the planets is in the task of three bodies. https://en.m.wikipedia.org/wiki/Three-body_problem

The eccentricity of the Earth’s orbit can be calculated using the following formula. E ≈ Vz / Vs.
Vz - Orbital velocity of the Earth.
Vs - "Orbital velocity of the Sun."
The orbital velocity of the Earth is one revolution in 1 year.
"Orbital velocity of the Sun" - one revolution in 250 million years.
E ≈ 1/250,000,000 ≈ 0.00000000 ...
---------------
The formula E ≈ Vz / Vs proves that the Sun does not rotate around any centers, but is in space, in a stationary state.

[Bored chemist]

Interesting. Looks like the OP has removed some posts that make him look even more foolish than normal.

I suspect that some of them had only been recently added.
It's hard to say it's likely to be conspiracy given how good the OP is at cockups.

The formula E ≈ Vz / Vs shows that the Sun does not rotate around the center of the galaxy.

That formula doesn't show anything.
It's just nonsense you made up.

"Orbital velocity of the Sun" - one revolution in 250 million years.

OK, That means that the Sun goes round the centre of the Galaxy once in 250000000 years.

he formula E ≈ Vz / Vs shows that the Sun does not rotate around the center of the galaxy.

But you just said that it does, once every 250000000 years.

You are arguing against yourself here.
Why not just accept that your formula is meaningless?

[Kryptid]

The eccentricity of the Earth’s orbit can be calculated using the following formula. E ≈ Vz / Vs.
Vz - Orbital velocity of the Earth.
Vs - "Orbital velocity of the Sun."
The orbital velocity of the Earth is one revolution in 1 year.
"Orbital velocity of the Sun" - one revolution in 250 million years.
E ≈ 1/250,000,000 ≈ 0.00000000 ...

Another wrong answer. The eccentricity of the Earth's orbit is about 0.0167, not zero.

Do you enjoy being wrong?

[Bored chemist]

I think he's trolling. Why else have a sig that says this?

The stupider the hypothesis, the easier it is to refute it, provided that the opponent is not stupid!

[Yusup Hizirov (OP)]

The eccentricity of the planetary satellite orbit also depends on the physical libration of the satellites, the reason for which is in the three-body problem. https://en.m.wikipedia.org/wiki/Libration
https://en.m.wikipedia.org/wiki/Three-body_problem

[Bored chemist]

The eccentricity of the planetary satellite orbit also depends on the physical libration of the satellites

No; it's the other way round.
The libration depends (in part) on the eccentricity.

the reason for which is in the three-body problem

No it isn't.
The Earth & Moon system is a 2 body problem. However, the other bodies- notably the Sun, do affect their motion. Which is another reason why your formula can't be right.

And, even if it was a 3 body problem, that still wouldn't be the reason for either the libration, or for the eccentricity.
You made two false statements, then said that one causes the other.
It's as stupid as saying
"All cats are green because all dogs are purple".
Why do you keep posting rubbish?
Are you in some sort of competition to see how much wrongness you can get into one post?

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the formula. E = (Vz: Ss) / (Vl: Sz) = 0.076

Where Vz - The speed of the Earth's rotation around the Sun - 8760 hours
Ss - The distance from the Sun to the Earth is 150,000,000 km.

Vl - The speed of rotation of the Moon around the Earth - 720 hours
Sz - Distance from Earth to Moon - 384,000 km.
0,001875
The eccentricity of the orbit of the moon varies from 0.044 to 0.072.

[Kryptid]

The eccentricity of the orbit of the moon can be calculated by the formula. E = Vz: Ss / Vl: Sz = 0.076

Finally, you admit that your original equation was wrong!

E = Vz: Ss / Vl: Sz = 0.076

The eccentricity of the orbit of the moon varies from 0.044 to 0.072.

You're aware that your answer is outside of that range, aren't you? So this equation doesn't work for the Moon either.

Does it work for Phobos?

Vz = 86,430 km/h
Ss = 227,939,200 km
Vl = 7,696.8 km/h
Sz = 9,376 km/h

E = (86,430/227,939,200)/(7,696.8/9,376)
E = (3.7918 x 10^-4)/(0.821)
E = 4.6185 x 10^-4

The correct answer is actually 0.0151. So it's even more wrong for Phobos than it is for the Moon.

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the formula. E ≈ (Vz / Ss) / (Vl / Sz) = 0.076

Where Vz - Orbital velocity of the Earth - 8760 km / h.
Ss - The distance from the Sun to the Earth is 150,000,000 km.

Vl - Orbital speed of the Moon - 720 km / h.
Sz - Distance from Earth to Moon - 384,000 km.
0,001875
The eccentricity of the orbit of the moon varies from 0.044 to 0.072.
---------------
The eccentricity of the orbit of a geostationary satellite can be calculated by the formula. E ≈ (Vz / Ss) / (Vi / Sz) = 0.000023

Where Vz - Orbital velocity of the Earth - 8760 km / h.
Ss - The distance between the Sun and the Earth is 150,000,000 km.

Vi - The satellite rotation speed around the Earth - 10800 km / h.
Sz - The distance between the Earth and the satellite is 42,000 km.