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Stationary model of the solar system

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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #180 on: 26/06/2020 08:58:34 »
Quote from: Yusup Hizirov on 26/06/2020 07:48:53
geological activity of the Earth
Meaningless thing
=
Quote from: Yusup Hizirov on 26/06/2020 07:48:53
(Vz: Ss) / (Ve: Rz)
Meaningless expression


Well, at least it isn't obviously wrong like that nonsense about eccentricity.
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Offline The Spoon

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Re: The Coriolis Force on Earth and in the Universe
« Reply #181 on: 26/06/2020 09:30:53 »
Quote from: Yusup Hizirov on 26/06/2020 07:48:53
The coefficient of the geological activity of the Earth can be calculated by the formula. E = (Vz: Ss) / (Ve: Rz) = 0,00021

Where Vz - Orbital velocity of the Earth - 8760 km / h.
Ss - The distance between the Sun and the Earth is 150,000,000 km.

Ve - Equatorial speed of rotation of the Earth: 1674 km / h
Rz - Radius of the Earth - 6,000 km.
More utter nonsense. You post an equation that makes no sense and fail to explain how it 'coefficient of geological activity' which appears to be a phrase you have made up to shoehorn into your ridiculous idea. You are effectively doing what TheBox did - making up things as you go along - especially meaningless equations.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #182 on: 26/06/2020 11:41:34 »
The geological activity coefficient of Venus can be determined by the formula. E ≈ Vэ / Vв = 0.0051
Vе - Equatorial velocity of Venus - 0.18 km / s.
Vв - Orbital velocity of Venus - 35 km / s.
---------------
Coefficient of geological activity of the Earth. E ≈ Ve / Vz = 0.0155
Vэ - Equatorial velocity of the Earth - 0.465 km / s.
Vz - Orbital velocity of the Earth - 30 km / s.
---------------
The coefficient of geological activity of Jupiter. E ≈ Vэ / Vю = 0.97
Vе - Equatorial velocity of Jupiter - 12.6 km / s.
Vю - The orbital velocity of Jupiter - 13 km / s.
« Last Edit: 26/06/2020 22:40:10 by Yusup Hizirov »
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Offline The Spoon

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Re: The Coriolis Force on Earth and in the Universe
« Reply #183 on: 26/06/2020 13:04:30 »
Quote from: Yusup Hizirov on 26/06/2020 11:41:34
The geological activity coefficient of Venus can be calculated by the formula. E ≈ Vэ / Vв = 0.0051
Ve - Equatorial rotation speed of Venus - 0.18 km / s.
Vв - Orbital velocity of Venus - 35 km / s.

Coefficient of geological activity of the Earth. E ≈ Ve / Vz = 0.0155
Ve - Equatorial speed of rotation of the Earth - 0.465 km / s.
Vz - Orbital velocity of the Earth - 30 km / s.

The coefficient of geological activity of Jupiter. E ≈ Vэ / Vю = 0.97
Vе - Equatorial rotation speed of Jupiter - 12.6 km / s.
Vю - The orbital velocity of Jupiter - 13 km / s.
I see you have resorted to the tactic of repeating the same old crap.
This is just trolling.
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #184 on: 26/06/2020 13:08:57 »
Quote from: Yusup Hizirov on 26/06/2020 11:41:34
The geological activity coefficient
Now all you need to do is find a use for it.
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Offline Kryptid

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Re: The Coriolis Force on Earth and in the Universe
« Reply #185 on: 26/06/2020 17:29:01 »
Quote from: Yusup Hizirov on 26/06/2020 07:48:53
The eccentricity of the orbit of the moon can be calculated by the formula. E = (Vz: Ss) / (Vl: Sz) = 0.076

Where Vz - Orbital velocity of the Earth - 8760 km / h.
Ss - The distance between the Sun and the Earth is 150,000,000 km.

Vl - The speed of rotation of the Moon around the Earth - 720 km / h.
Sz - Distance from Earth to Moon - 384,000 km.
0,001875
The eccentricity of the orbit of the moon varies from 0.044 to 0.072.

You think reposting a wrong answer will make it correct? 0.076 is still bigger than 0.072.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #186 on: 28/06/2020 17:35:13 »
Quote from: Yusup Hizirov on 23/02/2020 11:49:26
Secrets of the orbit of the moon.
From the foregoing, we can conclude that:
1) The Moon’s orbit is always extended along the Earth’s orbit and does not rotate counterclockwise, making one revolution in 8.8 years. https://en.m.wikipedia.org/wiki/Apsidal_precession
2) It is believed that at perihelion, the moon is at 50 thousand km. closer to Earth than aphelion, why is this huge difference not visually observed? https://images.app.goo.gl/wmqRKPc9jzScCrB16
3) The earth is in the center of the ellipse of the moon and not to the side, this can be easily checked. By measuring the time of the movement of the moon, from the new moon to the full moon and from the full moon to the new moon.
4) What force does not give the barycenter of the Earth and the Moon is in the center of the orbit of the Moon? http://regul238_f27w5b.radius-host.net/forum/zemlja-luna.gif
The moon does not move, 15 days from the new moon to the full moon and 14 days from the full moon to the new moon. https://images.app.goo.gl/wmqRKPc9jzScCrB16
« Last Edit: 29/06/2020 08:16:03 by Yusup Hizirov »
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Offline Kryptid

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Re: The Coriolis Force on Earth and in the Universe
« Reply #187 on: 28/06/2020 17:38:35 »
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #188 on: 28/06/2020 18:08:18 »
Quote from: Yusup Hizirov on 28/06/2020 17:35:13
The moon does not move from the new moon to the full moon for about 15 days, and from the full moon to the new moon for about 14 days.
Nobody said it did.
So, rather than talking nonsense, why don't you explain why you keep posting stuff that is plainly wrong?
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #189 on: 28/06/2020 18:11:29 »
Quote from: Kryptid on 28/06/2020 17:38:35
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
You're right
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #190 on: 28/06/2020 18:13:00 »
Quote from: Bored chemist on 28/06/2020 18:08:18
Quote from: Yusup Hizirov on 28/06/2020 17:35:13
The moon does not move, 15 days from the new moon to the full moon and 14 days from the full moon to the new moon. https://images.app.goo.gl/wmqRKPc9jzScCrB16
Nobody said it did.
So, rather than talking nonsense, why don't you explain why you keep posting stuff that is plainly wrong?
Show the error.
« Last Edit: 29/06/2020 08:17:44 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #191 on: 28/06/2020 18:52:18 »
Quote from: Yusup Hizirov on 28/06/2020 18:13:00
Show the error.
Take your pick
You were wrong about everything here- as I pointed out.

Quote from: Bored chemist on 23/06/2020 08:49:04
Quote from: Yusup Hizirov on 23/06/2020 08:02:19
Vl - Orbital velocity of the moon.
Vz - Orbital velocity of the Earth.
The orbital speed of the moon is one revolution in 720 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 720/8760 ≈ 0,082
Wrong.
Because the correct answer, as measured in reality, is 0.0549
Quote from: Yusup Hizirov on 23/06/2020 08:02:19
The eccentricity of the orbit of the geostationary satellites can be calculated by the following formula. E ≈ Vi / Vz
Where Vi is the satellite orbital velocity.
Vz - Orbital velocity of the Earth.
The satellite orbital speed is one revolution in 24 hours.
The orbital speed of the Earth is one revolution in 8760 hours.
E ≈ 24/8760 ≈ 0.0027
Wrong, because the eccentricity of geostationary satellites is variable. The range is from less than .0001 to 0.008.
Your formula says it's sonstant, so your formula is wrong.

Quote from: Yusup Hizirov on 23/06/2020 08:02:19
The eccentricity of the Phobos orbit can be calculated by the following formula. E ≈ Vf / Vm
Where Vf - Orbital velocity of Phobos.
Vm - Orbital velocity of Mars.
The orbital speed of Phobos is one revolution in 7.4 hours.
The orbital speed of Mars is one revolution in 16488 hours.
E ≈ 7.4 / 16488 ≈ 0.000448

The real answer  0.0151




Quote from: Yusup Hizirov on 23/06/2020 08:02:19
The eccentricity of the Deimos orbit can be calculated by the following formula. E ≈ Vd / Vm
Where Vd is the orbital velocity of Deimos.
Vm - Orbital velocity of Mars.
Deimos's orbital speed is one revolution in 30 hours.
The orbital speed of Mars is one revolution in 16488 hours.
30/16488 ≈ 0.0018

The real value i 0.00024

Quote from: Yusup Hizirov on 23/06/2020 08:02:19
The table of eccentricities of the orbits published on Wikipedia does not show by what formulas the table is compiled.
THEY ARE NOT COMPILED FROM A FORMULA. THEY ARE REAL MEASURED VALUES.

You get the wrong answer in every single case.
Why are you sticking to this nonsense?


Or we could go with the more recent version.



Now, why don't you explain why you keep posting stuff that is obviously wrong.
Quote from: Kryptid on 28/06/2020 17:38:35
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #192 on: 28/06/2020 19:58:45 »
Quote from: Yusup Hizirov on 28/06/2020 18:11:29
Quote from: Kryptid on 28/06/2020 17:38:35
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
You're right
(1km / s) / (30 km / s) = 0.33
Eccentricity of the moon's orbit 0.026 - 0.077. https://en.m.wikipedia.org/wiki/Orbit_of_the_Moon
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #193 on: 28/06/2020 20:12:45 »
Quote from: Yusup Hizirov on 28/06/2020 19:58:45
Quote from: Yusup Hizirov on 28/06/2020 18:11:29
Quote from: Kryptid on 28/06/2020 17:38:35
How about addressing the problem I raised (that 0.076 is larger than 0.072)?
You're right
(1km / s) / (30 km / s) = 0.33
Eccentricity of the moon's orbit 0.026 - 0.077. https://en.m.wikipedia.org/wiki/Orbit_of_the_Moon
We know we are right- we have the actual data on our side.
Now, please answer the question.


Quote from: Bored chemist on 28/06/2020 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #194 on: 29/06/2020 21:23:29 »
Quote from: Yusup Hizirov on 23/02/2020 11:49:26
The hypothesis of the formation of a record super new moon.
As we know, the length of the lunar ellipse depends on the orbital velocity of the Earth.
Every month, in the phase of the new moon, the Earth’s orbital velocity rises, which increases the length of the lunar ellipse. At the same time, the height of the lunar ellipse decreases accordingly, due to which, in the new moon phase, the Moon becomes closer to the Earth. And as a result, a super new moon is formed.
In winter at perihelion, the orbital velocity of the Earth rises.
During the coincidence of the perihelion of the Earth and the new moon, the orbital velocity of the Earth reaches its maximum value, due to which a record super new moon and super full moon are formed.
In the summer in aphelion, in the new moon phase, only the super new moon is formed.
Calendar of record super moons. https://predicalendar.ru/wiki/moon/super-moon/
December 3, 2017, Sunday
January 2, 2018, Tuesday
January 21, 2019, Monday
February 19, 2019, Tuesday.
https://en.m.wikipedia.org/wiki/Supermoon

Criticism of the existing theory of record super moon.
Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.
It means:
That every 8.8 years super moon happens.
And given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, then the super moon lasts about a year.
At the same time, if super moon occurs in perihelion, then in aphelion half a month later, a micro moon occurs.
But such a natural phenomenon is not observed in nature.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
https://en.m.wikipedia.org/wiki/Apsidal_precession
2) What force rotates the orbit of the moon?
3) Why the record-breaking super moon is not formed in the summer.
4) Why, a record super new moon, is more than a super full moon.
5) The major axis of the moon's ellipse is always elongated along the Earth’s orbit, and does not become perpendicular to the Earth’s orbit.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
6) The orbits of the satellites of the planets do not rotate and are always elongated along the orbits of the planets. And the orbits of the planets are spinning.
Then why, a record super moon, occurs every year and not after 8.8 years.
https://en.m.wikipedia.org/wiki/Apsidal_precession https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
« Last Edit: 03/07/2020 04:42:34 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #195 on: 29/06/2020 22:39:46 »
Quote from: Yusup Hizirov on 29/06/2020 21:23:29
Then why, a record super moon, occurs every year and not after 8.8 years.
Because they are different things.

Now, can you get back to the point?

Quote from: Bored chemist on 28/06/2020 20:12:45
Now, please answer the question.


Quote from: Bored chemist on Yesterday at 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #196 on: 30/06/2020 12:33:34 »
Quote from: Yusup Hizirov on 23/02/2020 11:49:26
Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.
It means:
That every 8.8 years super moon happens.
And given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, then the super moon lasts about a year.
At the same time, if super moon occurs in perihelion, then in aphelion half a month later, a micro moon occurs.
But such a natural phenomenon is not observed in nature.
https://en.m.wikipedia.org/wiki/Apsidal_precession
« Last Edit: 03/07/2020 04:47:00 by Yusup Hizirov »
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Offline Kryptid

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Re: The Coriolis Force on Earth and in the Universe
« Reply #197 on: 30/06/2020 14:24:06 »
Quote from: Yusup Hizirov on 28/06/2020 19:58:45
(1km / s) / (30 km / s) = 0.33

You know that 0.33 is much larger than 0.076, don't you?

Also, for Phobos/Mars, (2.138 km/s)/(24.007 km/s) = 0.0891. Phobos' orbital eccentricity is actually 0.0151. So it's still incorrect.
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #198 on: 30/06/2020 15:08:04 »
Quote from: Yusup Hizirov on 30/06/2020 12:33:34
Quote from: Yusup Hizirov on 23/02/2020 11:49:26
Super moon is an astronomical phenomenon that occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the moon's orbit.
It means:
1) That half a month after the super new moon, the micro full moon will come. https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
2) Given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, the super new moon and micro full moon, replacing each other, will last up to a year.
https://en.m.wikipedia.org/wiki/Apsidal_precession
None of that means anything much.

Quote from: Bored chemist on 29/06/2020 22:39:46
Now, can you get back to the point?

Quote from: Bored chemist on 28/06/2020 20:12:45
Now, please answer the question.


Quote from: Bored chemist on Yesterday at 18:52:18
Now, why don't you explain why you keep posting stuff that is obviously wrong.
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Offline The Spoon

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Re: The Coriolis Force on Earth and in the Universe
« Reply #199 on: 01/07/2020 09:36:33 »
Quote from: Yusup Hizirov on 30/06/2020 12:33:34
Given the fact that the moon’s orbit rotates extremely slowly
What does that even mean?
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