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  4. Can we use spheres with 2^n to show will to move (perpetual energy creation?)
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Can we use spheres with 2^n to show will to move (perpetual energy creation?)

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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #140 on: 13/10/2022 21:11:55 »
if perpetual systems are in cosmological systems, they include tesseracts. which allows (faster than light speeds). acting on energy and matter.

think of matter and energy as existing in a tesseract. 0.5 to 2.5.

They go dark as they are under heavy compression to travel faster.

* tesseract.png (183.97 kB, 2908x1974 - viewed 71 times.)
« Last Edit: 13/10/2022 21:19:28 by KiltedWeirdo »
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Offline Kryptid

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #141 on: 13/10/2022 21:21:42 »
Quote from: KiltedWeirdo on 13/10/2022 21:06:46
unless it's evidence of cosmological perpetual expansion.

The evidence for dark matter has nothing to do with the expansion of the Universe.
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #142 on: 13/10/2022 21:25:53 »
Quote from: Kryptid on 13/10/2022 21:21:42
Quote from: KiltedWeirdo on 13/10/2022 21:06:46
unless it's evidence of cosmological perpetual expansion.

The evidence for dark matter has nothing to do with the expansion of the Universe.
Funny, I've seen arguments for dark matter based on expansion. I guess it's each of our perception's.


shoot. that reads rudely. My bad. I guess it's the article sources.
« Last Edit: 13/10/2022 21:28:50 by KiltedWeirdo »
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #143 on: 13/10/2022 21:35:34 »
my work on collatz. if you can understand it. I tried to track movement of similar systems.
Like an expanded common multiplier with division, addition, subtraction and parenthesis included.
https://drive.google.com/file/d/1Rz2Ex6dzyaj4BYc4rtuMAk7bpGyYiJkj/view?usp=sharing
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Offline Bored chemist

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #144 on: 13/10/2022 22:04:27 »
Quote from: KiltedWeirdo on 13/10/2022 20:35:02
I cannot fathom what you mean.
Keep watching the video about Noether's theorem.
It might sink in eventually.
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Offline Kryptid

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #145 on: 13/10/2022 22:05:12 »
Quote from: KiltedWeirdo on 13/10/2022 21:25:53
Funny, I've seen arguments for dark matter based on expansion.

Where at? What were they?
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Offline Bored chemist

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #146 on: 13/10/2022 22:07:53 »
Quote from: KiltedWeirdo on 13/10/2022 20:30:48
evidence states dark matter has not been found.
Yes it has.
Quote from: KiltedWeirdo on 13/10/2022 20:30:48
alchemy was banned longer than science was.
As far as I'm aware, science was never really banned.
Quote from: KiltedWeirdo on 13/10/2022 20:35:02
if we have evidence, accepted conjecture of what is
We don't.
It's just that you think we do.
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #147 on: 13/10/2022 22:21:52 »
Quote from: Kryptid on 13/10/2022 22:05:12
Quote from: KiltedWeirdo on 13/10/2022 21:25:53
Funny, I've seen arguments for dark matter based on expansion.

Where at? What were they?
If i find one of them again, i'll be sure to link it here for you.

* time as matter to antimatter.png (226.58 kB, 5172x2030 - viewed 83 times.)
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #148 on: 13/10/2022 22:36:16 »
Quote from: Bored chemist on 13/10/2022 22:04:27
Quote from: KiltedWeirdo on 13/10/2022 20:35:02
I cannot fathom what you mean.
Keep watching the video about Noether's theorem.
It might sink in eventually.
you have a lot of stock in a theorem.
a general proposition not self-evident but proved by a chain of reasoning; a truth established by means of accepted truths.

* 3 6 9 of energy and mass.png (46.6 kB, 1615x1273 - viewed 74 times.)
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Offline Bored chemist

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #149 on: 13/10/2022 23:11:05 »
Quote from: KiltedWeirdo on 13/10/2022 22:36:16
you have a lot of stock in a theorem.
It's a mathematical theorem.
Once it is proved correct, that's it.
It is correct.

You are , in effect, saying "But what if 2 and 2 is not 4?".
That's not science, is it?
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #150 on: 13/10/2022 23:22:21 »
Quote from: Bored chemist on 13/10/2022 23:11:05
Quote from: KiltedWeirdo on 13/10/2022 22:36:16
you have a lot of stock in a theorem.
It's a mathematical theorem.
Once it is proved correct, that's it.
It is correct.

You are , in effect, saying "But what if 2 and 2 is not 4?".
That's not science, is it?
oh really? i'm saying 2+2 does not equal four? in effect.
please show me where i said anything similar.
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #151 on: 13/10/2022 23:23:01 »
you keep making pretty bold statements, sir.
Statements. When scientists ask questions.
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #152 on: 13/10/2022 23:25:12 »
½^n=2^-n (2 steps)

1/2n vs 1/2n+1 as 1/2y vs 1/2z+1 (2 steps vs 2 steps)

2n vs 2n+1 as 2a vs 2b+1 (2 steps vs 2 steps)

4n vs 4n+1 as 4c vs 4d+1 (4 steps vs 4 steps)

8n vs 8n+1 as 8e vs 8f+1 (8 steps vs 6 steps) (-2 steps)

16n vs 16n+1 as 16g vs 16h+1 (8 steps vs 12 steps) (+4 steps)

32n vs 32n+1 as 32i vs 32j+1 (32 steps vs 32 steps)

using -0.5,......,0.5 to find result via n





step would be n going from 1 to 2

quantity of stops available

steps/ quantity of stops available in steps

2n/2n+1 when n≥1 and whole number

2 steps/ 3 quantity of stops available in steps.

4 steps/ 5 quantity of stops available in steps.

6 steps/ 7 quantity of stops available in steps.

8 steps/ 9 quantity of stops available in steps.

12 steps/ 13 quantity of stops available in steps.

32 steps/ 33quantity of stops available in steps.





½^n=2^-n via 2 steps (including zero step)

n=(-1,0,1)

½^n=(2,0,½)

2^n=(½,0,2)





1/2y=-0.25 where y=-0.5

1/2y=0

1/2y=0.25 where y=0.5

Y uses 2 steps in 3 quantity of stops available in steps.





1/2z+1=0.75 where z=-0.5

1/2z+1=1 where z=0

1/2z+1=1.25 where z=0.5

Z uses 2 steps in 3 quantity of stops available in steps.





2a=-1 where a=-0.5

2a=0 where a=0

2a=1 where a=0.5

A uses 2 steps in 3 quantity of stops available in steps.





2b+1=0 where b=-0.5

2b+1=1 where b=0

2b+1=2 where b=0.5

B uses 2 steps in 3 quantity of stops available in steps.





4c=-2 where c=-0.5

4c=-1 where c=-0.25

4c=0 where c=0

4c=1 where c=0.25

4c=2 where c=0.5

C uses 4 steps in 5 quantity of stops available in steps.





4d+1=-1 where d=-0.5

4d+1=0 where d=-0.25

4d+1=1 where d=0

4d+1=2 where d=0.25

4d+1=3 where d=0.5

D uses 4 steps 5 quantity of stops available in steps.





8e=-4 where e=-0.5

8e=-3 where e=-0.375

8e=-2 where e=0.25

8e=-1 where e=-0.125

8e=0 where e=0

8e=1 where e=0.125

8e=2 where e=0.25

8e=3 where e=0.375

8e=4 where e=0.5

E uses 8 steps in 9 quantity of stops available in steps.





8f+1=-1 where f=-0.5

8f+1=0 where f=-0.125

8f+1=1 where f=0

8f+1=2 where f=0.125

8f+1=3 where f=0.25

8f+1=4 where f=0.375

8f+1=5 where f=0.5

F uses 6 steps in 7 quantity of stops available in steps.





16g=-4 where g=0.5

16g=-3 where g=-0.1875

16g=-2 where g=-0.25

16g=-1 where g=-0.0625

16g=0 where g=0

16g=1 where g=0.0625

16g=2 where g=0.25

16g=3 where g=0.1875

16g=4 where g=0.5

G uses 8 steps in 9 quantity of stops available in steps.





16h+1=-3 where h=-0.5

16h+1=-2 where h=-0.1875

16h+1=-1 where h=-0.125

16h+1=0 where h=-0.0625

16h+1=1 where h=0

16h+1=2 where g=0.03125

16h+1=3 where h=0.0125

16h+1=4 where h=0.1875

16h+1=5 where h=0.25

16h+1=6 where h=0.3125

16h+1=7 where h=0.375

16h+1=8 where h=0.4375

16h+1=9 where h=0.5

H uses 12 steps in 13 quantity of stops available in steps.





32i=-16 where i=-0.5

32i=-15 where i=-0.46875

32i=-14 where i=-0.4375

32i=-13 where i=-0.40625

32i=-12 where i=-0.375

32i=-11 where i=-0.34375

32i=-10 where i=-0.3125

32i=-9 where i=-0.28125

32i=-8 where i=-0.25

32i=-7 where i=-0.21875

32i=-6 where i=-0.1875

32i=-5 where i=-0.15625

32i=-4 where i=-0.125

32i=-3 where i=-0.09375

32i=-2 where i=-0.0625

32i=-1 where i=-0.03125

32i=0 where i=-0

32i=1 where i=0.03125

32i=2 where i=0.0625

32i=3 where i=0.09375

32i=4 where i=0.125

32i=5 where i=0.15625

32i=6 where i=0.1875

32i=7 where i=0.21875

32i=8 where i=0.25

32i=9 where i=0.28125

32i=10 where i=0.3125

32i=11 where i=0.34375

32i=12 where i=0.375

32i=13 where i=0.40625

32i=14 where i=0.4375

32i=15 where i=0.46875

32i=16 where i=0.5

I uses 32 steps in 33 quantity of stops available in steps.





32j+1=-15 where j=-0.5

32j+1=-14 where j=-0.46875

32j+1=-13 where j=-0.4375

32j+1=-12 where j=-0.40625

32j+1=-11 where j=-0.375

32j+1=-10 where j=-0.34375

32j+1=-9 where j=-0.3125

32j+1=-8 where j=-0.28125

32j+1=-7 where j=-0.25

32j+1=-6 where j=-0.21875

32j+1=-5 where j=-0.1875

32j+1=-4 where j=-15625

32j+1=-3 where j=-0.125

32j+1=-2 where j=-0.0.09375

32j+1=-1 where j=-0.0625

32j+1=0 where j=-0.03125

32j+1=1 where j=0

32j+1=2 where j=0.03125

32j+1=3 where j=0.0625

32j+1=4 where j=0.09375

32j+1=5 where j=0.125

32j+1=6 where j=0.15625

32j+1=7 where j=0.1875

32j+1=8 where j=0.21875

32j+1=9 where j=0.25

32j+1=10 where j=0.28125

32j+1=11 where j=0.3125

32j+1=12 where j=0.34375

32j+1=13 where j=0.375

32j+1=14 where j=0.40625

32j+1=15 where j=0.4375

32j+1=16 where j=0.46875

32j+1=17 where j=0.5

J uses 32 steps in 33 quantity of stops available in steps.



a to b

2n+1=3 as (-1,0,1) as a

2n+1=3 as (0,1,2) as b

bottom=+1

top=+1



b to c

2n+1=3 as (0,1,2) as b

2n+1=5 as (-2,-1,0,1,2) as c

bottom= -2

top=0



c to d

2n+1=5 as (-2,-1,0,1,2) as c

2n+1=5 as (-1,0,1,2,3,4) as d

bottm=+1

top=+2



d to e

2n+1=5 as (-1,0,1,2,3,4) as d

2n+1=9 as (-4,-3,-2,-1,0,1,2,3,4) as e

bottom=-3

top=0



e to f

2n+1=9 as (-4,-3,-2,-1,0,1,2,3,4) as e

2n+1=7 as (-1,0,1,2,3,4,5) as f

bottom=+3

top=+1



f to g

2n+1=7 as (-1,0,1,2,3,4,5) as f

2n+1=9 as (-4,-3,-2,-1,0,1,2,3,4) as g

bttom:-3

top=-1



g to h

2n+1=9 as (-4,-3,-2,-1,0,1,2,3,4) as g

2n+1=13 as (-3,-2,-1,0,1,2,3,4,5,6,7,8,9) as h

bottom=+1

top=+5



h to i

2n+1=13 as (-3,-2,-1,0,1,2,3,4,5,6,7,8,9) as h

2n+1=33 as (-16,-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16) as i

bottom=-13

top=+7



i to j

2n+1=33 as (-16,-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16) as i

2n+1=33 as (-15,-14,-13,-12,-11,-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17) as j

bottom=+1

top=+1
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Offline Bored chemist

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #153 on: 14/10/2022 08:48:36 »
Quote from: KiltedWeirdo on 13/10/2022 23:22:21
oh really? i'm saying 2+2 does not equal four? in effect.
please show me where i said anything similar.
OK, you said
Quote from: KiltedWeirdo on 11/10/2022 22:16:59
if Noether's theorem is flawed, perpetual motion can exist.
But we know it isn't because it's maths and proven.

So, the question you should be asking yourself is why you think something known to be true, might be false?
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #154 on: 14/10/2022 08:56:35 »
Quote from: Bored chemist on 14/10/2022 08:48:36
Quote from: KiltedWeirdo on 13/10/2022 23:22:21
oh really? i'm saying 2+2 does not equal four? in effect.
please show me where i said anything similar.
OK, you said
Quote from: KiltedWeirdo on 11/10/2022 22:16:59
if Noether's theorem is flawed, perpetual motion can exist.
But we know it isn't because it's maths and proven.

So, the question you should be asking yourself is why you think something known to be true, might be false?
Because the theorem has not been defeated yet, doesn't mean it can't be. proven is accepted, not stated as pure fact. our discernment of fact is not nature's discernment of fact. You may not realize this, but the whole of humanity itself is just as capable and culpable to mistakes as each of us as individuals. When higher stakes are involved, and people intentionally misleading things, (if they know and realize the truth) they can make things seem true and hard to counter, hard but not impossible. the mere existence of the stated perpetual system behind atomic sound and vibration is it's first strike. if something is allowed once, its an exception, if it's allowed twice, it's the break itself. so if perpetuality is behind any cosmological expansion, it's broken. Mankind's limits on engineering and production is why we won't attain a physical perpetuality mechanism of our own design. but inspecting the systems can still teach us a lot. otherwise please explain how breakdown of the 5 point particle system can break down to 3 atomic states with 5 being a prime. lol. I expect you to ignore this like all the other difficult questions i ask as you have done shown your ego. your inability to question what you believe to be true. We should question our results, and our path to arrive at them.
perpetual systems require exactly timed systems. not available with our production. it has to be just right. 0 margin of error. It requires nature's accuracy. Mankind's accuracy is not enough.

the question you should be asking yourself, how many scientists have narrow-mindedly or purposely added things that later turned out to be false, but for a time was accepted as a possible mechanic of physics or mathematics. (Religious people do get swayed by religious beliefs)
even Einstein unpublished his own theory of everything. Why, because Einstein could not solve it. why, because the 5 point particle system is flawed. it does not account for ghost particle interactions that effect charge. electrons are where we see major differences between atoms. that and number of protons and neutrons. but do the protons themselves really have differences by atomic number? do the neutrons?
keep in mind, a ghost particle is not a real particle, but is a reaction in particles that behaves like one, independently. this is most likely done as vibrations in the matter, in the area's between protons and neutrons. meaning we have to realize it's possible existence to even look for supporting data.

but i'm wrong. because you can't grasp the idea that a theorem writer might not have considered an unknown fact (matter to antimatter mutual destruction, with excess energy leftover) as time as the singularity. time being the interaction of force and matter, set by a flip particle. if protium lacks the neutron it should also lack the flip's interaction affects where deuterium should gain it and tritium should show high instability, because of it lacking its proton.
oh wait. from wiki.
Isotopes
Main article: Isotopes of hydrogen
Blausen 0530 HydrogenIsotopes.png

Hydrogen discharge (spectrum) tube

Deuterium discharge (spectrum) tube
Hydrogen has three naturally occurring isotopes, denoted 1
H, 2
H and 3
H. Other, highly unstable nuclei (4
H to 7
H) have been synthesized in the laboratory but not observed in nature.[54][55]

1
H is the most common hydrogen isotope, with an abundance of more than 99.98%. Because the nucleus of this isotope consists of only a single proton, it is given the descriptive but rarely used formal name protium.[56] It is unique among all stable isotopes in having no neutrons; see diproton for a discussion of why others do not exist.
2
H, the other stable hydrogen isotope, is known as deuterium and contains one proton and one neutron in the nucleus. All deuterium in the universe is thought to have been produced at the time of the Big Bang, and has endured since that time. Deuterium is not radioactive, and does not represent a significant toxicity hazard. Water enriched in molecules that include deuterium instead of normal hydrogen is called heavy water. Deuterium and its compounds are used as a non-radioactive label in chemical experiments and in solvents for 1
H-NMR spectroscopy.[57] Heavy water is used as a neutron moderator and coolant for nuclear reactors. Deuterium is also a potential fuel for commercial nuclear fusion.[58]
3
H is known as tritium and contains one proton and two neutrons in its nucleus. It is radioactive, decaying into helium-3 through beta decay with a half-life of 12.32 years.[50] It is so radioactive that it can be used in luminous paint, making it useful in such things as watches. The glass prevents the small amount of radiation from getting out.[59] Small amounts of tritium are produced naturally by the interaction of cosmic rays with atmospheric gases; tritium has also been released during nuclear weapons tests.[60] It is used in nuclear fusion reactions,[61] as a tracer in isotope geochemistry,[62] and in specialized self-powered lighting devices.[63] Tritium has also been used in chemical and biological labeling experiments as a radiolabel.[64]
Unique among the elements, distinct names are assigned to its isotopes in common use today. During the early study of radioactivity, various heavy radioactive isotopes were given their own names, but such names are no longer used, except for deuterium and tritium. The symbols D and T (instead of 2
H and 3
H) are sometimes used for deuterium and tritium, but the symbol P is already in use for phosphorus and thus is not available for protium.[65] In its nomenclatural guidelines, the International Union of Pure and Applied Chemistry (IUPAC) allows any of D, T, 2
H, and 3
H to be used, although 2
H and 3
H are preferred.[66]

The exotic atom muonium (symbol Mu), composed of an antimuon and an electron, can also be considered a light radioisotope of hydrogen.[67] Because muons decay with lifetime 2.2 µs, muonium is too unstable to exhibit observable chemistry.[68] Nevertheless, muonium compounds are important test cases for quantum simulation, due to the mass difference between the antimuon and the proton,[69] and IUPAC nomenclature incorporates such hypothetical compounds as muonium chloride (MuCl) and sodium muonide (NaMu), analogous to hydrogen chloride and sodium hydride respectively.[70]


tritium has one electron to two flips, causing instability.
« Last Edit: 14/10/2022 09:19:36 by KiltedWeirdo »
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #155 on: 14/10/2022 09:20:10 »
tritium has two flips to one electron, causing instability.

* Tritium.png (37.21 kB, 1270x1051 - viewed 85 times.)
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #156 on: 14/10/2022 09:32:20 »
why does deuterium seem stable while tritium is highly radioactive? the flip ghost particle that is not an actual particle, but exists in charge caused by the electron and proton and neutron patterns. the inside is a square. it allows a charged side to follow the electron. which creates comfort patterns in 4 points in a line. it can be an electron with positive interactions or negative.
if its negative poles of the neutron and proton its interacting with, it sets the middle to positive. --+-
if its positive poles of the neutron and proton its interacting with, it sets the middle to negative. -+-+
which has more to do with what its electron passed by before than it does on the patterns itself.
--+-
-+-+
--+-
-+-+
--+-
-+-+
--+-
-+-+
is one full spin of the electron around deuterium.

* PXL_20220826_172906348.jpg (2025.94 kB, 4080x3072 - viewed 78 times.)
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #157 on: 14/10/2022 09:39:14 »
Helium-2 or 2
He
 is an extremely unstable isotope of helium. Its nucleus, a diproton, consists of two protons with no neutrons.

highly unstable with two PROTONS. NO NEUTRONS. NO flip ghost particle.
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #158 on: 14/10/2022 09:41:23 »
The flip particle changes, at the speed of light. it goes -,+,-,+,-,+. Oh wait. So does odds, evens, odds, evens.
it's so fast we can't record it.

it might just effect 1 quality, 2 or three. charge, mass, and spin. Of the neutron, and only of a paired proton.
tritium might pair one neutron to two protons.
it would link radioactive decay directly to balance of neutron and proton.
further evidence of a perpetual based nature of time.
duality is mass and energy.
singularity is time.
the duality depends on singularity movements. conversion always requires time. time is a part of force. force requires mass and acceleration. acceleration includes speed, distance, and time.
time is pretty stable. but we can edit distance to affect speed, by 2n+1 where 2^n=1/2^-n.
by halving distance, we double speed.
at a point, vibrations turn to spin.
the angle of magnets and position should allow the flux lines to work as artificial entanglements. that's how they realize where they can go, creating will to move.
« Last Edit: 14/10/2022 10:03:51 by KiltedWeirdo »
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Offline KiltedWeirdo (OP)

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Re: Can we use spheres with 2^n to show will to move (perpetual energy creation?)
« Reply #159 on: 14/10/2022 11:07:58 »
I guess my work is against science. wait a minute.

* stability.jpg (69.72 kB, 625x592 - viewed 75 times.)

* horus eye 3 layers.png (31.73 kB, 936x1089 - viewed 68 times.)

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