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Quote from: Yusup Hizirov on 21/08/2018 21:38:38Quote from: Bored chemist on 10/08/2018 18:13:18But until the tides stop corresponding to the position of the moon, nobody is going to believe any suggestion that the tides are not driven mainly by the moon.October 3, 1869, the amplitude of the tide in the Bay of Fundy was 5 meters.October 4, 1869 amplitude of the tide in the Bay of Fundy was 21 meters (Once in the history of observation).For one day in the Bay of Fundy, the amplitude of the tides increased from 5 to 21 meters, 4-fold.Question. What has changed in the Bay of Fundy in one day.1. Gravitation.2. The coastline3. Inclination of the moon.4. Rotational speed of the whirlpool.https://en.m.wikipedia.org/wiki/1869_Saxby_GaleSharp fluctuations in the amplitude of tides occur not only in the Bay of Fundy, but also in other bays where rivers flow. You can read the encyclopediahttps://www.encyclopedia.com/earth-and-environment/geology-and-oceanography/geology-and-oceanography/tides https://www.1902encyclopedia.com/T/TID/tides.html
Quote from: Bored chemist on 10/08/2018 18:13:18But until the tides stop corresponding to the position of the moon, nobody is going to believe any suggestion that the tides are not driven mainly by the moon.October 3, 1869, the amplitude of the tide in the Bay of Fundy was 5 meters.October 4, 1869 amplitude of the tide in the Bay of Fundy was 21 meters (Once in the history of observation).For one day in the Bay of Fundy, the amplitude of the tides increased from 5 to 21 meters, 4-fold.Question. What has changed in the Bay of Fundy in one day.1. Gravitation.2. The coastline3. Inclination of the moon.4. Rotational speed of the whirlpool.https://en.m.wikipedia.org/wiki/1869_Saxby_Gale
But until the tides stop corresponding to the position of the moon, nobody is going to believe any suggestion that the tides are not driven mainly by the moon.
Who is ready to refute or recognize this theory.
Quote from: Yusup Hizirov on 29/08/2018 22:06:46Congratulations, you are free from medieval prejudices.Yes we are, but you are notQuote from: Yusup Hizirov on 02/09/2018 07:44:19Silence of opponents shows that they do not have a constructive counterargument.Last resort of the pseudo scientist.Answers have been provided, but ignored. No point wasting more time. eg:Quote from: Colin2B on 30/08/2018 09:05:02Again, you are being selective with the data. If you look at a map of the world you will see that the equator passes through very few coastal places whereas the 2 temperate zones include a large number of coastal sites, so your two samples are not comparable.As I pointed out before, your precession theory would result in larger tides at the equator than anywhere else, so the onus is on you to provide the evidence.In reality the maximum tidal bulge follows the moon’s orbit which does not follow the equator. Many people mistakenly think it does and so make an incorrect assumption.Quote from: Bored chemist on 18/08/2018 12:48:40You say your "theory" solves all the problems.Please show us ho you would use it to calculate (as an example) the times of the next few high tides in London, New York or Barcelona or some other place where we can check.If you can't do that then your idea doesn't even solve the simplest problem.Unfortunately you are avoiding answering @Bored chemist and looking at your post I can see why.Quote from: Yusup Hizirov on 18/08/2018 13:55:47The length of the tidal wave depends on the diameter of the whirlpool. And the height of the tidal wave depends on the rotation speed of the whirlpool of the orbital velocity of the Earth, and the time of the tilting of the whirlpool (12 hours).A = V1 • V2 / twhere: A is the amplitude of the tidal wave (precession angle).V1 - rotation speed of the whirlpool.V2 is the orbital velocity of the Earth.t - the time of tilting of the whirlpool (12 hours).The first problem with this formula is that it does not return an amplitude, it produces a number of square metres per second. That is clearly wrong.Next problem involves timing:Quote from: Yusup Hizirov on 18/08/2018 13:55:47As is known, everything that rotates, including whirlpools, possess the property of a gyro (yule) to maintain the vertical position of the axis in space, regardless of the rotation of the Earth.If you look at the Earth from the Sun, the whirlpools, rotating together with the Earth, turn over twice a day, due to which the whirlpools precess (swing by 1-2 degrees) and reflect the tidal wave around the entire perimeter of the whirlpool.A rigid gyroscope on earth will indeed align itself to the sidereal day which is 4mins shorter than the solar day. However, that gives a number of problems for your theory.Firstly, we know from observation that the main tide period is period is about 12hrs 25mins - half a lunar day - so two tides take 24hrs 50mins which is the average time for the Earth to rotate once relative to the Moon. This is a hugh difference from your difference of 4mins in 24hrs making your double tide period 23hrs 56mins. Clearly your predictions can never work with this theory.Your precession theory is also flawed because we are not dealing with a rigid gyroscope, so rather than turning over the water level would rise at one edge until gravity restrained it, leading to a constant level.Quote from: The Spoon on 29/08/2018 21:21:47I have sailed in the Severn estuary several times and have yet to encounter these whirlpools you seem to think are present. They don’t exist in the channel or north sea either. He is confusing tidal wave circulation with currents and doesn’t understand the difference.There are so many false assumptions in these various topics that is hardly worth the effort of replying, especially as the op isn’t listening and just keeps repeating the same old false claims.
Congratulations, you are free from medieval prejudices.
Silence of opponents shows that they do not have a constructive counterargument.
Again, you are being selective with the data. If you look at a map of the world you will see that the equator passes through very few coastal places whereas the 2 temperate zones include a large number of coastal sites, so your two samples are not comparable.As I pointed out before, your precession theory would result in larger tides at the equator than anywhere else, so the onus is on you to provide the evidence.In reality the maximum tidal bulge follows the moon’s orbit which does not follow the equator. Many people mistakenly think it does and so make an incorrect assumption.Quote from: Bored chemist on 18/08/2018 12:48:40You say your "theory" solves all the problems.Please show us ho you would use it to calculate (as an example) the times of the next few high tides in London, New York or Barcelona or some other place where we can check.If you can't do that then your idea doesn't even solve the simplest problem.Unfortunately you are avoiding answering @Bored chemist and looking at your post I can see why.Quote from: Yusup Hizirov on 18/08/2018 13:55:47The length of the tidal wave depends on the diameter of the whirlpool. And the height of the tidal wave depends on the rotation speed of the whirlpool of the orbital velocity of the Earth, and the time of the tilting of the whirlpool (12 hours).A = V1 • V2 / twhere: A is the amplitude of the tidal wave (precession angle).V1 - rotation speed of the whirlpool.V2 is the orbital velocity of the Earth.t - the time of tilting of the whirlpool (12 hours).The first problem with this formula is that it does not return an amplitude, it produces a number of square metres per second. That is clearly wrong.Next problem involves timing:Quote from: Yusup Hizirov on 18/08/2018 13:55:47As is known, everything that rotates, including whirlpools, possess the property of a gyro (yule) to maintain the vertical position of the axis in space, regardless of the rotation of the Earth.If you look at the Earth from the Sun, the whirlpools, rotating together with the Earth, turn over twice a day, due to which the whirlpools precess (swing by 1-2 degrees) and reflect the tidal wave around the entire perimeter of the whirlpool.A rigid gyroscope on earth will indeed align itself to the sidereal day which is 4mins shorter than the solar day. However, that gives a number of problems for your theory.Firstly, we know from observation that the main tide period is period is about 12hrs 25mins - half a lunar day - so two tides take 24hrs 50mins which is the average time for the Earth to rotate once relative to the Moon. This is a hugh difference from your difference of 4mins in 24hrs making your double tide period 23hrs 56mins. Clearly your predictions can never work with this theory.Your precession theory is also flawed because we are not dealing with a rigid gyroscope, so rather than turning over the water level would rise at one edge until gravity restrained it, leading to a constant level.Quote from: The Spoon on 29/08/2018 21:21:47I have sailed in the Severn estuary several times and have yet to encounter these whirlpools you seem to think are present. They don’t exist in the channel or north sea either. He is confusing tidal wave circulation with currents and doesn’t understand the difference.There are so many false assumptions in these various topics that is hardly worth the effort of replying, especially as the op isn’t listening and just keeps repeating the same old false claims.
You say your "theory" solves all the problems.Please show us ho you would use it to calculate (as an example) the times of the next few high tides in London, New York or Barcelona or some other place where we can check.If you can't do that then your idea doesn't even solve the simplest problem.
The length of the tidal wave depends on the diameter of the whirlpool. And the height of the tidal wave depends on the rotation speed of the whirlpool of the orbital velocity of the Earth, and the time of the tilting of the whirlpool (12 hours).A = V1 • V2 / twhere: A is the amplitude of the tidal wave (precession angle).V1 - rotation speed of the whirlpool.V2 is the orbital velocity of the Earth.t - the time of tilting of the whirlpool (12 hours).
As is known, everything that rotates, including whirlpools, possess the property of a gyro (yule) to maintain the vertical position of the axis in space, regardless of the rotation of the Earth.If you look at the Earth from the Sun, the whirlpools, rotating together with the Earth, turn over twice a day, due to which the whirlpools precess (swing by 1-2 degrees) and reflect the tidal wave around the entire perimeter of the whirlpool.
I have sailed in the Severn estuary several times and have yet to encounter these whirlpools you seem to think are present.
The vortex theory of tides can be easily verified by the connection between the height of the tidal wave and the rotation speed of the whirlpools.The list of seas with an average swirl speed of more than 0.5 km / h, and an average tidal wave height of more than 5 cm:Irish Sea, North Sea, Barents Sea, Baffin Sea, White Sea, Bering Sea, Sea of Okhotsk, Arabian Sea, Sargasso Sea, Hudson Bay, Maine Bay, Gulf of Alaska. etc..The list of seas with an average swirl speed of less than 0.5 km / h, and an average tidal wave height of less than 5 cm:The Baltic Sea, the Greenland Sea, the Black Sea, the Sea of Azov, the Caspian Sea, the Chukchi Sea, the Kara Sea, the Laptev Sea, the Red Sea, the Marmara Sea, the Caribbean Sea, the Sea of Japan, the Gulf of Mexico, etc.Note: The height of the tidal wave (soliton) and the amplitude of the tides is not the same.
Quote from: Yusup Hizirov on 02/09/2018 09:27:04The vortex theory of tides can be easily verified by the connection between the height of the tidal wave and the rotation speed of the whirlpools.The list of seas with an average swirl speed of more than 0.5 km / h, and an average tidal wave height of more than 5 cm:Irish Sea, North Sea, Barents Sea, Baffin Sea, White Sea, Bering Sea, Sea of Okhotsk, Arabian Sea, Sargasso Sea, Hudson Bay, Maine Bay, Gulf of Alaska. etc..The list of seas with an average swirl speed of less than 0.5 km / h, and an average tidal wave height of less than 5 cm:The Baltic Sea, the Greenland Sea, the Black Sea, the Sea of Azov, the Caspian Sea, the Chukchi Sea, the Kara Sea, the Laptev Sea, the Red Sea, the Marmara Sea, the Caribbean Sea, the Sea of Japan, the Gulf of Mexico, etc.Note: The height of the tidal wave (soliton) and the amplitude of the tides is not the same.Why is the height of the tides in the Baltic Sea 10 cm, and in the White Sea 10 meters.And check the rotation speed of the whirlpool (flow velocity).http://www.bibliotekar.ru/7-more-okean/10.htm
It is believed that in the Baltic and White Sea tidal current moves from the Atlantic Ocean.You can explain the mechanics of this movement.
Quote from: Yusup Hizirov on 02/09/2018 09:30:14Quote from: Yusup Hizirov on 02/09/2018 09:27:04The vortex theory of tides can be easily verified by the connection between the height of the tidal wave and the rotation speed of the whirlpools.The list of seas with an average swirl speed of more than 0.5 km / h, and an average tidal wave height of more than 5 cm:Irish Sea, North Sea, Barents Sea, Baffin Sea, White Sea, Bering Sea, Sea of Okhotsk, Arabian Sea, Sargasso Sea, Hudson Bay, Maine Bay, Gulf of Alaska. etc..The list of seas with an average swirl speed of less than 0.5 km / h, and an average tidal wave height of less than 5 cm:The Baltic Sea, the Greenland Sea, the Black Sea, the Sea of Azov, the Caspian Sea, the Chukchi Sea, the Kara Sea, the Laptev Sea, the Red Sea, the Marmara Sea, the Caribbean Sea, the Sea of Japan, the Gulf of Mexico, etc.Note: The height of the tidal wave (soliton) and the amplitude of the tides is not the same.Why is the height of the tides in the Baltic Sea 10 cm, and in the White Sea 10 meters.And check the rotation speed of the whirlpool (flow velocity).http://www.bibliotekar.ru/7-more-okean/10.htmYou seem to have answered your own question.Google's translation of the page you cited says "In narrow places, in straits, tidal currents reach a tremendous speed. So in the narrow part of the White Sea - in the so-called Throat - tidal currents reach a speed of 15 kilometers per hour.What are the causes of this phenomenon?The main culprit of the tides is the Moon and, to a lesser extent, the Sun. "
Quote from: Colin2B on 02/09/2018 08:19:21I have sailed in the Severn estuary several times and have yet to encounter these whirlpools you seem to think are present. Whirlpools cyclones and anticyclones are not possible to see not armed with the eye, they are too big. And the wind and current can be seen.
This is not an answer!
Quote from: Yusup Hizirov on 02/09/2018 09:27:04The vortex theory of tides can be easily verified by the connection between the height of the tidal wave and the rotation speed of the whirlpools.The list of seas with an average swirl speed of more than 0.5 km / h, and an average tidal wave height of more than 5 cm:Irish Sea, North Sea, Barents Sea, Baffin Sea, White Sea, Bering Sea, Sea of Okhotsk, Arabian Sea, Sargasso Sea, Hudson Bay, Maine Bay, Gulf of Alaska. etc..The list of seas with an average swirl speed of less than 0.5 km / h, and an average tidal wave height of less than 5 cm:The Baltic Sea, the Greenland Sea, the Black Sea, the Sea of Azov, the Caspian Sea, the Chukchi Sea, the Kara Sea, the Laptev Sea, the Red Sea, the Marmara Sea, the Caribbean Sea, the Sea of Japan, the Gulf of Mexico, etc.Note: The height of the tidal wave (soliton) and the amplitude of the tides is not the same.Why is the height of the tides in the Baltic Sea 10 cm, and in the White Sea 10 meters.And check the rotation speed of the whirlpool (flow velocity). http://tapemark.narod.ru/more/22.pnghttp://www.bibliotekar.ru/7-more-okean/10.htm
Please answer the question
Quote from: Yusup Hizirov on 02/09/2018 09:27:04The vortex theory of tides can be easily verified by the connection between the height of the tidal wave and the rotation speed of the whirlpools.The list of seas with an average swirl speed of more than 0.5 km / h, and an average tidal wave height of more than 5 cm:Irish Sea, North Sea, Barents Sea, Baffin Sea, White Sea, Bering Sea, Sea of Okhotsk, Arabian Sea, Sargasso Sea, Hudson Bay, Maine Bay, Gulf of Alaska. etc..The list of seas with an average swirl speed of less than 0.5 km / h, and an average tidal wave height of less than 5 cm:The Baltic Sea, the Greenland Sea, the Black Sea, the Sea of Azov, the Caspian Sea, the Chukchi Sea, the Kara Sea, the Laptev Sea, the Red Sea, the Marmara Sea, the Caribbean Sea, the Sea of Japan, the Gulf of Mexico, etc.Note: The height of the tidal wave (soliton) and the amplitude of the tides is not the same.
Please read this post carefully and you will be free from heresy.
Quote from: Yusup Hizirov on 02/09/2018 11:23:37Please read this post carefully and you will be free from heresy.That makes no sense.Please try answering the question.What's wrong with the model where the Sun and Moon create the tides?
You consciously leave the answer.Call the sea where there are high tides, but there is no fast flow.
Call the sea where there are high tides, but there is no fast flow.
Quote from: Yusup Hizirov on 02/09/2018 09:27:04Why is the height of the tides in the Baltic Sea 10 cm, and in the White Sea 10 meters.And check the rotation speed of the whirlpool (flow velocity).http://www.bibliotekar.ru/7-more-okean/10.htmPlease answer the question
Why is the height of the tides in the Baltic Sea 10 cm, and in the White Sea 10 meters.And check the rotation speed of the whirlpool (flow velocity).http://www.bibliotekar.ru/7-more-okean/10.htm
Quote from: Yusup Hizirov on 02/09/2018 12:52:50Call the sea where there are high tides, but there is no fast flow.