[Yusup Hizirov (OP)]

The geological activity coefficient of Mercury can be calculated using the following formula.
E ≈ (Vm / Sm) / (Vm / Rm) = 0.003 / 0.0045 = 0.66
----------------
Where Vm - The orbital speed of Mercury - 174,000 km / h.
Sm - The distance from the Sun to Mercury is 58,000,000 km.
------------------
Where Vm - Equatorial rotation speed of Mercury - 11 km / h.
Rm - Mercury radius - 2400 km.
*************
The geological activity coefficient of Venus can be calculated using the following formula.
E ≈ (Vв / Sв) / (Vв / Rв) = 0.0011 / 0.010 = 0.11
----------------
Where Vz - Orbital velocity of Venus - 126000 km / h.
Sz - The distance from the Sun to Venus is 110,000,000 km.
------------------
Where Vz - Equatorial rotation speed of Venus - 6.52 km / h.
Rz - Radius of Venus - 6000 km.
****************************
The geological activity coefficient of the Earth can be calculated by the following formula.
E ≈ (Vz / Ss) / (Vl / Rz) = 0.00071 / 0.26 = 0.0027
----------------
Where Vz - Orbital velocity of the Earth - 107 000 km / h.
Sz - The distance from the Sun to the Earth is 150,000,000 km.
--------------
Where Vz - Equatorial speed of rotation of the Earth - 1700 km / h.
Rz - Radius of the Earth - 6500 km.
*********************************
The geological activity coefficient of Jupiter can be calculated using the following formula.
E ≈ (Vyu / Syu) / (Vyu / Ryu) = 0.000061 / 0.64 = 0.000095
----------------
Where Vy - The orbital speed of Jupiter - 47052 km km / h.
Syu - The distance from the Sun to Jupiter is 770,000,000 km.
--------------
Where Vy - Equatorial rotation speed of Jupiter - 45000 km / h.
Ryu - Jupiter radius - 70,000 km.

[Bored chemist]

The geological activity coefficient

You still haven't said what it is.

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vl / Vz = 28/365 = 0,076

Liar

The eccentricity of the orbit of the moon can be calculated by the following formula. E ≈ Vz / Vl = 30/360 = 0,083
Where Vz - Orbital velocity of the Earth - 30 degrees / month.
Vl - Orbital velocity of the moon - 360 degrees / month.
---
The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.074
Where Vz - Orbital velocity of the Earth - 107 000 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000
Where Vl - Orbital velocity of the moon - 3680 km / h.
Sl - Distance from the Earth to the Moon 384 000км.
The eccentricity of the orbit of the moon varies, from 0.026 to 0.077.

[Bored chemist]

The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ Vz / Vl = 30/360 = 0,083

Do you know what "liar" means?
It means someone who says something which they know is not true.
Now the real value for the eccentricity is, on average  0.0549, and you know that because you have been told repeatedly.
And, more importantly, it varies as you say, from 0.026 to 0.077.

And you keep saying it doesn't.
You keep saying it's a fixed value
 30/360 = 0,083
which you know isn't true.

Why do you keep doing that?

Why do you say it is fixed and also say that it varies?

[Yusup Hizirov (OP)]

The eccentricity of the orbit of the moon can be calculated by the following formula. E ≈ Vz / Vl = 30/360 = 0,083
Where Vz - Orbital velocity of the Earth - 30 degrees / month.
Vl - Orbital velocity of the moon - 360 degrees / month.
---
The eccentricity of the orbit of the moon can be calculated by the following formula.
E ≈ (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.074
Where Vz - Orbital velocity of the Earth - 107 000 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000
Where Vl - Orbital velocity of the moon - 3680 km / h.
Sl - Distance from the Earth to the Moon 384 000км.
The eccentricity of the orbit of the moon varies, from 0.026 to 0.077.

Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.

[The Spoon]

Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.

What utter nonsense. It is becoming increasingly clear your idiotic statements are just trolling.

[Yusup Hizirov (OP)]

Please point out exactly where the error is and why it is an error. Otherwise you are in danger of being considered a troll.

[The Spoon]

Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.

See the above.

[Yusup Hizirov (OP)]

The eccentricity of the Moon's orbit can be calculated using the following formula. E = Vz / Vl = 0.0411 / 0.55 = 0.0747
Where Vz - Earth's orbital speed - 0.0411 degrees / hour.
Vl - Moon's orbital speed - 0.55 degrees / hour.

The eccentricity of the Moon's orbit can be calculated using the following formula.
E = (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.0747
Where Vz is the Earth's orbital speed - 107,218 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000 km.
Where Vl is the Moon's orbital speed - 3683 km / h.
Sl - Distance from the Earth to the Moon 384,000 km.
The eccentricity of the Moon's orbit varies, from 0.026 to 0.077.
------------
Both formulas show that the average eccentricity of the Moon's orbit is 0.0747.
And the average eccentricity of the Moon's orbit, which is determined using radar, is 0.054.
http://www.aggregateria.com/R/radiolokatsionnaja_astronomija.html

Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.

Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity, and it is not possible to calculate the eccentricity with high accuracy.

[Bored chemist]

Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity,

Go on then... show that it determines something.

[Yusup Hizirov (OP)]

The hypothesis of the formation of a record super-new moon.
As we know the length of the lunar ellipse depends on the orbital velocity of the Earth.
The monthly orbital velocity of the Earth increases monthly in the new moon phase, which increases the length of the lunar ellipse. At the same time, the height of the lunar ellipse decreases accordingly, due to which, in the new moon phase, the Moon becomes closer to the Earth, and as a result a super-new moon is formed.
In winter at perihelion, the orbital velocity of the Earth rises.
During the coincidence of the perihelion of the Earth and the new moon, the orbital velocity of the Earth reaches its maximum value, due to which a record super-new moon and super-full moon are formed.
In the summer in aphelion, in the new moon phase, only the super-new moon is formed.
Calendar of record super moons. https://predicalendar.ru/wiki/moon/super-moon/
December 3, 2017, Sunday
January 2, 2018, Tuesday
January 21, 2019, Monday
February 19, 2019, Tuesday.
https://en.m.wikipedia.org/wiki/Supermoon

Criticism of the existing theory of record super moon.
Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.
It means:
That every 8.8 years super moon happens.
And given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, then the super moon lasts about a year.
At the same time, if the moon is super full in perihelion, then in the aphelion, after half a month, micro new moon should occur.
But such a natural phenomenon is not observed in nature.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
https://en.m.wikipedia.org/wiki/Apsidal_precession
2) What force rotates the orbit of the moon?
3) Why the record-breaking super moon is not formed in the summer.
4) Why is the record super new moon more than the super full moon.
5) The orbit of the moon does not rotate and does not make one revolution in 8.8 years. Because, the Solar Coriolis effect, once a month stretches the orbit of the Moon along the orbit of the Earth. And the orbits of the planets of the solar system rotate. https://ru.m.wikipedia.org/wiki/%D0%A1%D0%BC%D0%B5%D1%89%D0%B5%D0%BD%D0%B8%D0%B5_%D0%BF%D0%B5%D1%80%D0%B8%D0%B3%D0%B5%D0%BB%D0%B8%D1%8F_%D0%9C%D0%B5%D1%80%D0%BA%D1%83%D1%80%D0%B8%D1%8F

6) The major axis of the moon's ellipse is always elongated along the Earth’s orbit, and does not become perpendicular to the Earth’s orbit.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA

The orbit of the moon does not rotate and does not make one revolution in 8.8 years. Because, the Solar Coriolis effect, once a month stretches the orbit of the Moon along the orbit of the Earth. And the orbits of the planets of the solar system rotate.

[Bored chemist]

The orbit of the moon does not rotate

Yes it does.
https://en.wikipedia.org/wiki/Lunar_precession

does not make one revolution in 8.8 years.

Well, it might be nearer to 8.9 but that's not a major issue
https://en.wikipedia.org/wiki/Apsidal_precession

And it's also not that simple, there are other axes.


Why do you post stuff that's obviously wrong?

[Yusup Hizirov (OP)]

In winter, on the second day after the new moon, when the Earth's orbital speed reaches its maximum value, a record super-new moon is formed, and in the northern hemisphere, maximum tides are formed.

[Bored chemist]

In winter, on the second day after the new moon, when the Earth's orbital speed reaches its maximum value, a record super-new moon is formed,...

What is a "super-new moon"?
A super Moon is big a new Moon is small.

[Yusup Hizirov (OP)]

Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity,

Go on then... show that it determines something.

To determine the orbital angular velocity of the Earth, it is sufficient to multiply the angular velocity of the Moon by the eccentricity of the Moon's orbit.
Vz ≈ Vl × E ≈ 360 × 0.083
Also, you can check the orbital speed of other planets.

[Bored chemist]

Let's check.

angular velocity of the Moon

OK
The orbital period is
27.321661 days
Which is
2,360,591.5 seconds
So the velocity is
4.2362 * 10^-7 Hz
2.6617 e-6 rads per second

eccentricity of the Moon's orbit.

And that's
0.0549

orbital angular velocity of the Earth

OK that's once every 365.24 days
31,556,736
And a frequency of
3.16889e-8 Hz
And an angular velocity of
1.9911e-7 rad/sec

OK, so, what you are saying is that you
"multiply the angular velocity of the Moon by the eccentricity of the Moon's orbit."
To get "the orbital angular velocity of the Earth"

OK that's
multiply 2.6617 e-6 rads per second by 0.0549
To get  1.9911e-7 rad/sec
But that's not the answer you get from that multiplication, is it?
 You can save a lot of scrabbling with arithmetic by working in reciprocal days as a unit.

 orbital angular velocity of the Earth
1/365.24
0.0027379257
angular velocity of the Moon
1/27.321661
0.0366009958

And the ratio is
0.07480
Which isn't 0.0549

Also, you can check the orbital speed of other planets.

Why bother?
It doesn't work with the Earth and the Moon.

[Bored chemist]

This idea hasn't got any better since we first pointed out that it was wrong.

The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083

You know that's the wrong answer, don't you?

It's not just that it's the wrong answer (the right answer is nearer to 1/13 than 1/12), but it's the wrong answer to the wrong question.

The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.

No, it isn't.
And there's no reason to imagine that it would be.
The right answer is about 0.0549.

[Yusup Hizirov (OP)]

orbital angular velocity of the Earth
1/365.24
0.0027379257
angular velocity of the Moon
1/27.321661
0.0366009958

And the ratio is
0.07480
Which isn't 0.0549

The eccentricity of the Moon's orbit can be approximately calculated using the following formula.
E ≈ (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.074
Where Vz is the Earth's orbital speed - 107,218 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000
Where Vl is the Moon's orbital speed - 3683 km / h.
Sl - Distance from the Earth to the Moon 384 000 km.
The eccentricity of the Moon's orbit varies, from 0.026 to 0.077.

Both formulas show the same result, this is no coincidence. 0.074

[Bored chemist]

this is no coincidence.

It certainly isn't a coincidence.
Because 0.074 is a number and .026 to 0.077is a range.
So they are not even the same sort of thing.

[Kryptid]

Both formulas show the same result

A result that is wrong.