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  4. The Coriolis Force on Earth and in the Universe
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The Coriolis Force on Earth and in the Universe

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Offline The Spoon

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Re: The Coriolis Force on Earth and in the Universe
« Reply #240 on: 08/07/2020 13:12:41 »
Quote from: Yusup Hizirov on 08/07/2020 07:39:33
Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.
What utter nonsense. It is becoming increasingly clear your idiotic statements are just trolling.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #241 on: 08/07/2020 13:56:53 »
Quote from: Colin2B on 03/07/2020 08:05:30
Please point out exactly where the error is and why it is an error. Otherwise you are in danger of being considered a troll.
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Offline The Spoon

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Re: The Coriolis Force on Earth and in the Universe
« Reply #242 on: 08/07/2020 13:59:10 »
Quote from: Yusup Hizirov on 08/07/2020 07:39:33
Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.
See the above.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #243 on: 09/07/2020 12:41:43 »
Quote from: Yusup Hizirov on 08/07/2020 07:39:33
Quote from: Yusup Hizirov on 06/07/2020 21:26:46
The eccentricity of the Moon's orbit can be calculated using the following formula. E = Vz / Vl = 0.0411 / 0.55 = 0.0747
Where Vz - Earth's orbital speed - 0.0411 degrees / hour.
Vl - Moon's orbital speed - 0.55 degrees / hour.

The eccentricity of the Moon's orbit can be calculated using the following formula.
E = (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.0747
Where Vz is the Earth's orbital speed - 107,218 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000 km.
Where Vl is the Moon's orbital speed - 3683 km / h.
Sl - Distance from the Earth to the Moon 384,000 km.
The eccentricity of the Moon's orbit varies, from 0.026 to 0.077.
------------
Both formulas show that the average eccentricity of the Moon's orbit is 0.0747.
And the average eccentricity of the Moon's orbit, which is determined using radar, is 0.054.
http://www.aggregateria.com/R/radiolokatsionnaja_astronomija.html
Satellites that are in resonance between themselves and with the planet, as a rule, move stably and move away from the planet.
And satellites that do not resonate with the planet move randomly, somersault, change eccentricity and approach the planet.
The eccentricity of satellites is also affected by the physical libration of planetary satellites, the nature of which is in the three-body problem.
Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity, and it is not possible to calculate the eccentricity with high accuracy.
« Last Edit: 22/07/2020 13:01:01 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #244 on: 09/07/2020 12:45:03 »
Quote from: Yusup Hizirov on 09/07/2020 12:41:43
Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity,
Go on then... show that it determines something.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #245 on: 10/07/2020 10:36:27 »
Quote from: Yusup Hizirov on 23/02/2020 11:49:26
The hypothesis of the formation of a record super-new moon.
As we know the length of the lunar ellipse depends on the orbital velocity of the Earth.
The monthly orbital velocity of the Earth increases monthly in the new moon phase, which increases the length of the lunar ellipse. At the same time, the height of the lunar ellipse decreases accordingly, due to which, in the new moon phase, the Moon becomes closer to the Earth, and as a result a super-new moon is formed.
In winter at perihelion, the orbital velocity of the Earth rises.
During the coincidence of the perihelion of the Earth and the new moon, the orbital velocity of the Earth reaches its maximum value, due to which a record super-new moon and super-full moon are formed.
In the summer in aphelion, in the new moon phase, only the super-new moon is formed.
Calendar of record super moons. https://predicalendar.ru/wiki/moon/super-moon/
December 3, 2017, Sunday
January 2, 2018, Tuesday
January 21, 2019, Monday
February 19, 2019, Tuesday.
https://en.m.wikipedia.org/wiki/Supermoon

Criticism of the existing theory of record super moon.
Super moon - occurs when the full moon or new moon coincides with perigee, as a result of the rotation of the orbit of the moon. At a speed of one revolution in 8.8 years.
It means:
That every 8.8 years super moon happens.
And given the fact that the moon’s orbit rotates extremely slowly, 1 revolution in 8.8 years, then the super moon lasts about a year.
At the same time, if the moon is super full in perihelion, then in the aphelion, after half a month, micro new moon should occur.
But such a natural phenomenon is not observed in nature.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
https://en.m.wikipedia.org/wiki/Apsidal_precession
2) What force rotates the orbit of the moon?
3) Why the record-breaking super moon is not formed in the summer.
4) Why is the record super new moon more than the super full moon.
5) The orbit of the moon does not rotate and does not make one revolution in 8.8 years. Because, the Solar Coriolis effect, once a month stretches the orbit of the Moon along the orbit of the Earth. And the orbits of the planets of the solar system rotate. https://ru.m.wikipedia.org/wiki/%D0%A1%D0%BC%D0%B5%D1%89%D0%B5%D0%BD%D0%B8%D0%B5_%D0%BF%D0%B5%D1%80%D0%B8%D0%B3%D0%B5%D0%BB%D0%B8%D1%8F_%D0%9C%D0%B5%D1%80%D0%BA%D1%83%D1%80%D0%B8%D1%8F

6) The major axis of the moon's ellipse is always elongated along the Earth’s orbit, and does not become perpendicular to the Earth’s orbit.
https://images.app.goo.gl/aRfBpPhE2eTMB3YaA
The orbit of the moon does not rotate and does not make one revolution in 8.8 years. Because, the Solar Coriolis effect, once a month stretches the orbit of the Moon along the orbit of the Earth. And the orbits of the planets of the solar system rotate.
« Last Edit: 10/07/2020 16:19:15 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #246 on: 10/07/2020 13:26:10 »
Quote from: Yusup Hizirov on 10/07/2020 10:36:27
The orbit of the moon does not rotate
Yes it does.
https://en.wikipedia.org/wiki/Lunar_precession

Quote from: Yusup Hizirov on 10/07/2020 10:36:27
does not make one revolution in 8.8 years.
Well, it might be nearer to 8.9 but that's not a major issue
https://en.wikipedia.org/wiki/Apsidal_precession

And it's also not that simple, there are other axes.


Why do you post stuff that's obviously wrong?
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #247 on: 11/07/2020 00:36:24 »
In winter, on the second day after the new moon, when the Earth's orbital speed reaches its maximum value, a record super-new moon is formed, and in the northern hemisphere, maximum tides are formed.
« Last Edit: 11/07/2020 09:58:21 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #248 on: 11/07/2020 10:10:42 »
Quote from: Yusup Hizirov on 11/07/2020 00:36:24
In winter, on the second day after the new moon, when the Earth's orbital speed reaches its maximum value, a record super-new moon is formed,...
What is a "super-new moon"?
A super Moon is big a new Moon is small.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #249 on: 20/07/2020 12:16:11 »
Quote from: Bored chemist on 09/07/2020 12:45:03
Quote from: Yusup Hizirov on 09/07/2020 12:41:43
Using the formula E = Vz / Vl, it is possible to determine with great accuracy the dependence of the eccentricity on the orbital velocity,
Go on then... show that it determines something.
To determine the orbital angular velocity of the Earth, it is sufficient to multiply the angular velocity of the Moon by the eccentricity of the Moon's orbit.
Vz ≈ Vl × E ≈ 360 × 0.083
Also, you can check the orbital speed of other planets.
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #250 on: 20/07/2020 13:40:59 »
Let's check.
Quote from: Yusup Hizirov on 20/07/2020 12:16:11
angular velocity of the Moon
OK
The orbital period is
27.321661 days
Which is
2,360,591.5 seconds
So the velocity is
4.2362 * 10^-7 Hz
2.6617 e-6 rads per second


Quote from: Yusup Hizirov on 20/07/2020 12:16:11
eccentricity of the Moon's orbit.
And that's
0.0549
Quote from: Yusup Hizirov on 20/07/2020 12:16:11
orbital angular velocity of the Earth
OK that's once every 365.24 days
31,556,736
And a frequency of
3.16889e-8 Hz
And an angular velocity of
1.9911e-7 rad/sec

OK, so, what you are saying is that you
"multiply the angular velocity of the Moon by the eccentricity of the Moon's orbit."
To get "the orbital angular velocity of the Earth"

OK that's
multiply 2.6617 e-6 rads per second by 0.0549
To get  1.9911e-7 rad/sec
But that's not the answer you get from that multiplication, is it?
 You can save a lot of scrabbling with arithmetic by working in reciprocal days as a unit.

 orbital angular velocity of the Earth
1/365.24
0.0027379257
angular velocity of the Moon
1/27.321661
0.0366009958

And the ratio is
0.07480
Which isn't 0.0549

Quote from: Yusup Hizirov on 20/07/2020 12:16:11
Also, you can check the orbital speed of other planets.
Why bother?
It doesn't work with the Earth and the Moon.
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #251 on: 20/07/2020 13:48:02 »
This idea hasn't got any better since we first pointed out that it was wrong.
Quote from: Bored chemist on 19/06/2020 17:06:48
Quote from: Kryptid on 19/06/2020 14:26:30
Quote from: Yusup Hizirov on 18/06/2020 22:21:11
The Earth’s orbital speed is 30 degrees per month.
The orbital speed of the moon is 360 degrees per month.
E = 30/360 = 0.083

You know that's the wrong answer, don't you?
It's not just that it's the wrong answer (the right answer is nearer to 1/13 than 1/12), but it's the wrong answer to the wrong question.



Quote from: Yusup Hizirov on 18/06/2020 22:21:11
The eccentricity of the orbit of the moon can be calculated by the following formula. E = Vz / Vl
Where Vz - Orbital velocity of the Earth.
Vl - Orbital velocity of the moon.
No, it isn't.
And there's no reason to imagine that it would be.
The right answer is about 0.0549.

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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #252 on: 20/07/2020 22:00:01 »
Quote from: Bored chemist on 20/07/2020 13:40:59
orbital angular velocity of the Earth
1/365.24
0.0027379257
angular velocity of the Moon
1/27.321661
0.0366009958

And the ratio is
0.07480
Which isn't 0.0549
The eccentricity of the Moon's orbit can be approximately calculated using the following formula.
E ≈ (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.074
Where Vz is the Earth's orbital speed - 107,218 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000
Where Vl is the Moon's orbital speed - 3683 km / h.
Sl - Distance from the Earth to the Moon 384 000 km.
The eccentricity of the Moon's orbit varies, from 0.026 to 0.077.

Both formulas show the same result, this is no coincidence. 0.074
« Last Edit: 20/07/2020 23:17:34 by Yusup Hizirov »
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Offline Bored chemist

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Re: The Coriolis Force on Earth and in the Universe
« Reply #253 on: 20/07/2020 22:12:05 »
Quote from: Yusup Hizirov on 20/07/2020 22:00:01
this is no coincidence.
It certainly isn't a coincidence.
Because 0.074 is a number and .026 to 0.077is a range.
So they are not even the same sort of thing.
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Offline Kryptid

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Re: The Coriolis Force on Earth and in the Universe
« Reply #254 on: 20/07/2020 22:38:09 »
Quote from: Yusup Hizirov on 20/07/2020 22:00:01
Both formulas show the same result

A result that is wrong.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #255 on: 20/07/2020 22:44:37 »
Both formulas show the result - 0.074
« Last Edit: 20/07/2020 23:16:22 by Yusup Hizirov »
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Re: The Coriolis Force on Earth and in the Universe
« Reply #256 on: 21/07/2020 00:34:39 »
Quote from: Yusup Hizirov on 20/07/2020 22:44:37
Both formulas show the result - 0.074

0.074 is wrong, so both formulas are wrong.
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Offline Yusup Hizirov (OP)

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Re: The Coriolis Force on Earth and in the Universe
« Reply #257 on: 21/07/2020 01:53:18 »
The eccentricity of the Moon's orbit can be calculated using the following formula. E = Vz / Vl = 0.0411 / 0.55 = 0.0747
Where Vz - Earth's orbital speed - 0.0411 degrees / hour.
Vl - Moon's orbital speed - 0.55 degrees / hour.

The eccentricity of the Moon's orbit can be calculated using the following formula.
E = (Vz / Sz) / (Vl / Sl) = 0.00071 / 0.0095 = 0.0747
Where Vz is the Earth's orbital speed - 107,218 km / h.
Sz - Distance from the Sun to the Earth - 150,000,000 km.
Where Vl is the Moon's orbital speed - 3683 km / h.
Sl - Distance from the Earth to the Moon 384,000 km.
The eccentricity of the Moon's orbit varies, from 0.026 to 0.077.
------------
Both formulas show that the average eccentricity of the Moon's orbit is 0.0747.
And the average eccentricity of the Moon's orbit, which is determined using radar, is 0.054.
http://www.aggregateria.com/R/radiolokatsionnaja_astronomija.html
« Last Edit: 22/07/2020 13:03:29 by Yusup Hizirov »
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Offline Kryptid

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Re: The Coriolis Force on Earth and in the Universe
« Reply #258 on: 21/07/2020 04:46:01 »
Quote from: Yusup Hizirov on 21/07/2020 01:53:18
Then, according to these two formulas, the distance from the Sun to the Earth will not be 150 but 200 m. km.

All the more reason to discount your formulas as wrong.

Check your results in advance and make sure they are correct before posting them. The fact that you keep posting wrong answers over and over again makes it look like you are trying to waste everyone's time.
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Re: The Coriolis Force on Earth and in the Universe
« Reply #259 on: 21/07/2020 08:50:13 »
Come back to us when you have a formula that works for Venus and Mercury with eccentricities of 0.0068 and 0.2056 respectively.

Don't come back with the same wrong formula because that's just trolling.
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