[guest39538]

I think (u) may be the mass in your question and V would be the occupied volume of space

Wait a minute... in order to find out the size of an atom, you have to input the volume of an atom into the equation? That's circular reasoning, as the volume of an atom is already a measure of its size...

And the size is proportional to   volume is a volume of space .

[Kryptid]

And the size is proportional to   volume is a volume of space .

Again, are you saying that you already have to know what the volume of an atom is in order to use this equation?

[guest39538]

I meant, as part of your demonstration that you are not talking nonsense, by calculating the heat of combustion of hydrogen, you would need to know  the internal energy of oxygen.


I'm guessing you need the same  parameter for hydrogen.
Anything else?
You aren't going to suddenly decide that you need the rate of change of density of jupiter's 23rd biggest satellite or something like that?

No not at all lol , what ever that means

My equation is just a simplified equation that explains almost everything . 

I mean ask a question , how big is an atom ?

V==4/3 π r³ / t

What's exothermic process ?

x=

Why do gases expand when heated ?

>V =

It has so many uses , quite magical . 

Ok. If they as you claim, explain these things, give a simple explanation of how they do so.

Ok, consider a metal block with dimensions xyz ,

 

If you increase the magnitude of E³ you increase the volume ,the block expands .

[The Spoon]

It's used to calculate almost everything ,  you just have to put in the values . 

So what values would I need to supply in order for the equation to show me the amount of energy released when hydrogen burns in oxygen?

Well you'd have to be really good at math to work that out  because that would be   the value of u would be the value of hydrogens u . 

What you are asking is for the deeper more complex side of the simplified equation , which is meant for higher education .

I don't know the values personally , that is why I came up with the equation , I don't need to know the intricates for the simplified version to understand the process  and physics of almost everything by using the equation .

So essentially what you are saying is, you claim to have created an 'equation' but you don't know what any of the parameters or operators stand for. That is not an equation, it is a random collection of symbols that are meaningless. You really don't understand what equations are do you? You think that all you need to do is throw some impressive looking symbols in will do. Sloppy, like all of your thinking. But then, you are just pratting about aren't you pigeon?

[guest39538]

And the size is proportional to   volume is a volume of space .

Again, are you saying that you already have to know what the volume of an atom is in order to use this equation?

No, concerning atoms , it tells you why the volume of atom is the volume of an atom because the internal energy is divided by the volume of space stretching the atom giving it form and dimensions , exothermic reaction and transitional state of bonded energies .

V = = 4/3 π r³/t  see how that works now ?

[guest39538]

So essentially what you are saying is, you claim to have created an 'equation' but you don't know what any of the parameters or operators stand for. That is not an equation, it is a random collection of symbols that are meaningless. You really don't understand what equations are do you? You think that all you need to do is throw some impressive looking symbols in will do. Sloppy, like all of your thinking. But then, you are just pratting about aren't you pigeon?

I've already explained it is a simplified generalised equation that explains almost everything in one maths answer . It is not meant to have intricate details , it is meant as a teaching aid of physics process and generalised math for that process .

It can be used to answer a variation of questions . 

What changes in the caesium when the frequency changes ?

Δf = Δv =Δ

Added- why does a snowman melt ?

Δ

[Kryptid]

No, concerning atoms , it tells you why the volume of atom is the volume of an atom

So then you can't use it to calculate the size of an atom?

I'm trying to give you a fair opportunity to prove that your equation works and can give the right answers. So why don't you give us an example of something that can indeed be accurately calculated with the equation? I'll even help you do the math.

[The Spoon]

I meant, as part of your demonstration that you are not talking nonsense, by calculating the heat of combustion of hydrogen, you would need to know  the internal energy of oxygen.


I'm guessing you need the same  parameter for hydrogen.
Anything else?
You aren't going to suddenly decide that you need the rate of change of density of jupiter's 23rd biggest satellite or something like that?

No not at all lol , what ever that means

My equation is just a simplified equation that explains almost everything . 

I mean ask a question , how big is an atom ?

V==4/3 π r³ / t

What's exothermic process ?

x=

Why do gases expand when heated ?

>V =

It has so many uses , quite magical . 

Ok. If they as you claim, explain these things, give a simple explanation of how they do so.

Ok, consider a metal block with dimensions xyz ,

 

If you increase the magnitude of E³ you increase the volume ,the block expands .

Deliberately avoiding the question please explain what each symbol represents and how it is relevant to the specific thing you claim it calculates.

Also, explain why the following statement is true:

'If you increase the magnitude of E³ you increase the volume ,the block expands'

Explain using words not what you claim to be maths so that the concept can be assessed.

[guest39538]

No, concerning atoms , it tells you why the volume of atom is the volume of an atom

So then you can't use it to calculate the size of an atom?

I'm trying to give you a fair opportunity to prove that your equation works and can give the right answers. So why don't you give us an example of something that can indeed be accurately calculated with the equation? I'll even help you do the math.

A bit shocked , thanks for the offer of help , much appreciated .

How about we try the density of an electrical field ?
→
ρE = = ρ0

Or the change of time ?

Δt =  Δ 

Or the size of a singularity ?

V = 

mass?

m = 

I only use the number 1 for my values , for example an atoms density = 1 , E = 1 , volume = 1 , u = 1.

[guest39538]

Deliberately avoiding the question please explain what each symbol represents and how it is relevant to the specific thing you claim it calculates. Also, explain why the following statement is true:'If you increase the magnitude of E³ you increase the volume ,the block expands'Explain using words not what you claim to be maths so that the concept can be assessed.

u is internal energy  and any volume of u  absorbs energy and reradiates this energy . The absorbing of energy expressed *E³ because it's isotropic in nature , so if you have a ''cold'' metal block the ''hot'' is attracted to that block isotropic .  The block will then try to retain an equilibrium and divide this gained energy by the surrounding volume of the block .  Additionally the block itself expands because the whole of the block  tries to divide itself by the surrounding space but the blocks binary bond helps to retain form by pulling back .

[Bored chemist]

OK, here's a question somebody already asked.
How much heat is released by the  combustion of hydrogen?

What inputs do you need?

Are you talking about the energy released when an hydrogen atom is split or the heat energy that is generated by kinetics between the friction of particles ?

If I take, for example, 1 litre of hydrogen and burn it in a blowtorch and have the heat and fumes from that blowtorch heat some water how much heat is transferred to the water (assuming none is wasted).

Some set up like the "simple calorimeter" pictured on this page.
http://staff.um.edu.mt/ratk1/Energetics.htm

[guest39538]

OK, here's a question somebody already asked.
How much heat is released by the  combustion of hydrogen?

What inputs do you need?

Are you talking about the energy released when an hydrogen atom is split or the heat energy that is generated by kinetics between the friction of particles ?

If I take, for example, 1 litre of hydrogen and burn it in a blowtorch and have the heat and fumes from that blowtorch heat some water how much heat is transferred to the water (assuming none is wasted).

Some set up like the "simple calorimeter" pictured on this page.
http://staff.um.edu.mt/ratk1/Energetics.htm

Well

ΔT=Δ  of the water

What is your equation for this and I'll see if my equation works for this . 

[Bored chemist]

I don't have "an equation".
But I have what you asked for- a value for u for hydrogen.

[Kryptid]

I only use the number 1 for my values , for example an atoms density = 1 , E = 1 , volume = 1 , u = 1.

I guess that means you weren't telling the truth when you said that you were using metric units, because an atom's density is not 1 kilogram per cubic meter, its energy is not 1 joule, etc.

[guest39538]

I only use the number 1 for my values , for example an atoms density = 1 , E = 1 , volume = 1 , u = 1.

I guess that means you weren't telling the truth when you said that you were using metric units, because an atom's density is not 1 kilogram per cubic meter, its energy is not 1 joule, etc.

I said I use 1, you'd use the standard measurements . Like I said it's a generalised equation .

Probably the most useful useless equation ever devised .

[guest39538]

I don't have "an equation".
But I have what you asked for- a value for u for hydrogen.

Ok, could you provide that value and please explain how the value was derived ?

[Kryptid]

Ok, could you provide that value and please explain how the value was derived ?

I think it's better if we wait and tell you after you use your equation to calculate the energy. That way we can be more sure that you were using your equation and only your equation to get the answer instead of attempting to get the answer by working backwards.

[jeffreyH]

I think we should hear about the dimensional analysis you used in deriving your equation. And if you spout any nonsense I might be tempted to ban you permanently. How's that?

[Bored chemist]

I don't have "an equation".
But I have what you asked for- a value for u for hydrogen.

Ok, could you provide that value and please explain how the value was derived ?

As you already said, u is the internal energy calculated as given here
https://en.wikipedia.org/wiki/Internal_energy

so, it's not as if I can move the goalposts.
Now please tell me what you intend to do with the value I give, in order to calculate the heat of combustion.

[guest39538]

I don't have "an equation".
But I have what you asked for- a value for u for hydrogen.

Ok, could you provide that value and please explain how the value was derived ?

As you already said, u is the internal energy calculated as given here
https://en.wikipedia.org/wiki/Internal_energy

so, it's not as if I can move the goalposts.
Now please tell me what you intend to do with the value I give, in order to calculate the heat of combustion.

No idea , I don't  use that , you'd use that because you know what it means , I use my own version which is

u= = 1E  = V

u of course , the natural state is really cold , u only becomes hot when *E  and we get some kinetics between atoms to create heat energy .

Frozen water demonstrates this .

Hydrogen doesn't combust as such , the hydrogen electron shells ''surface''  becomes super heated and looks like its fire .

u*E³ = ΔkE = ΔT

So

kE = E/V

There may be some new tech , I don't want to say too much though because of giving it away , you understand the importance of more. tech right ?