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  4. 5d interwoven model and tensor force .
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5d interwoven model and tensor force .

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Offline The Spoon

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  • Re: 5d interwoven model and tensor force .
    « Reply #140 on: 02/04/2019 22:43:53 »
    Quote from: Thebox on 02/04/2019 22:41:52
    Quote from: Kryptid on 02/04/2019 22:39:22
    Quote from: Thebox on 02/04/2019 22:36:35
    Well in theory yes

    Then that is what I'm trying to do. If "u" is equal to the net electric charge in a hydrogen molecule, then "u" has to be zero.
    Well yes if we're being honest , can we call this , the idol moment ?


    What Billy Idol? 😆
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #141 on: 02/04/2019 22:48:43 »
    Quote from: Kryptid on 02/04/2019 22:43:03
    Quote from: Thebox on 02/04/2019 22:41:52
    Well yes if we're being honest , can we call this , the idol moment ?

    Okay then, so what would "E" represent in the equation in normal science language?

    Difficult to answer but I think in your terms we can use hf³ with the same net charge .
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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #142 on: 02/04/2019 22:51:15 »
    Quote from: Thebox on 02/04/2019 22:48:43
    Difficult to answer but I think in your terms we can use hf³

    I assume "h" means Planck's constant. Does the "f" mean frequency? What would frequency represent for a hydrogen molecule? The frequency of the chemical bond?
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #143 on: 02/04/2019 22:53:57 »
    Quote from: Kryptid on 02/04/2019 22:51:15
    Quote from: Thebox on 02/04/2019 22:48:43
    Difficult to answer but I think in your terms we can use hf³

    I assume "h" means Planck's constant. Does the "f" mean frequency? What would frequency represent for a hydrogen molecule? The frequency of the chemical bond?
    The frequency of incoming hf I'm referring to , I'm not sure about your chemical bond but I imagine the frequency speeds up some what when ''heated''  to combustion ?

    And yes a constant ,
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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #144 on: 02/04/2019 22:56:14 »
    Quote from: Thebox on 02/04/2019 22:53:57
    The frequency of incoming hf I'm referring to , I'm not sure about your chemical bond but I imagine the frequency speeds up some what when ''heated''  to combustion ?

    It sounds like your equation assumes ignition by photons. Which means we can use any kind of photon frequency we want here, I guess?
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  • Re: 5d interwoven model and tensor force .
    « Reply #145 on: 02/04/2019 22:56:23 »
    Quote from: The Spoon on 02/04/2019 22:43:53
    Quote from: Thebox on 02/04/2019 22:41:52
    Quote from: Kryptid on 02/04/2019 22:39:22
    Quote from: Thebox on 02/04/2019 22:36:35
    Well in theory yes

    Then that is what I'm trying to do. If "u" is equal to the net electric charge in a hydrogen molecule, then "u" has to be zero.
    Well yes if we're being honest , can we call this , the idol moment ?


    What Billy Idol? 😆

    White wedding , a mixture of frequencies .

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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #146 on: 02/04/2019 22:58:02 »
    Quote from: Kryptid on 02/04/2019 22:56:14
    Quote from: Thebox on 02/04/2019 22:53:57
    The frequency of incoming hf I'm referring to , I'm not sure about your chemical bond but I imagine the frequency speeds up some what when ''heated''  to combustion ?

    It sounds like your equation assumes ignition by photons. Which means we can use any kind of photon frequency we want here, I guess?
    Yes I think so , obvious the shorter the wave length , the quicker combustion is achieved .
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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #147 on: 02/04/2019 23:00:52 »
    Quote from: Thebox on 02/04/2019 22:58:02
    Yes I think so , obvious the shorter the wave length , the quicker combustion is achieved .

    Now we're making some progress. I assume that "V" is simply the volume of the hydrogen gas. So now on to "t", which is, I'm guessing, the time taken to burn the hydrogen. Depending on how the system is set up, you could burn hydrogen as fast or as slow as you want to. So can any number be put in for "t"? How about ten seconds?
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  • Re: 5d interwoven model and tensor force .
    « Reply #148 on: 02/04/2019 23:07:45 »
    Quote from: Kryptid on 02/04/2019 23:00:52
    Quote from: Thebox on 02/04/2019 22:58:02
    Yes I think so , obvious the shorter the wave length , the quicker combustion is achieved .

    Now we're making some progress. I assume that "V" is simply the volume of the hydrogen gas. So now on to "t", which is, I'm guessing, the time taken to burn the hydrogen. Depending on how the system is set up, you could burn hydrogen as fast or as slow as you want to. So can any number be put in for "t"? How about ten seconds?
    Ten seconds will do , consider also there is the volume of the hydrogen and volume external of the hydrogen unless you're talking about a compression chamber  and a hydrogen fuel engine .
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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #149 on: 02/04/2019 23:09:09 »
    Quote from: Thebox on 02/04/2019 23:07:45
    Ten seconds will do , consider also there is the volume of the hydrogen and volume external of the hydrogen unless your talking about a compression chamber  and a hydrogen fuel engine .

    As a gas, hydrogen will fill whatever container it's in. So those volumes can be taken as equal if you'd like.
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #150 on: 02/04/2019 23:12:32 »
    Quote from: Kryptid on 02/04/2019 23:09:09
    Quote from: Thebox on 02/04/2019 23:07:45
    Ten seconds will do , consider also there is the volume of the hydrogen and volume external of the hydrogen unless your talking about a compression chamber  and a hydrogen fuel engine .

    As a gas, hydrogen will fill whatever container it's in. So those volumes can be taken as equal if you'd like.

    Arr , ok, I see what you're on about , pressure equalling density I presume ?  Obviously density also plays a part , there will be more energy per mm³ of hydrogen if pressured compared to less pressured .


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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #151 on: 02/04/2019 23:15:09 »
    Quote from: Thebox on 02/04/2019 23:12:32
    Arr , ok, I see what you're on about , pressure equalling density I presume ?  Obviously density also plays a part , there will be more energy per mm³ of hydrogen if pressured compared to less pressured .

    If we are assuming normal atmospheric pressure, then knowing that we have one gram of hydrogen will already give us the volume (and therefore the density).

    Unless you have anything else to add, I think I have all I need to do the math. Should I start?

    EDIT: I've got to go do something, but I'll be back in a little bit.
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  • Re: 5d interwoven model and tensor force .
    « Reply #152 on: 02/04/2019 23:16:37 »
    Quote from: Kryptid on 02/04/2019 23:15:09
    Quote from: Thebox on 02/04/2019 23:12:32
    Arr , ok, I see what you're on about , pressure equalling density I presume ?  Obviously density also plays a part , there will be more energy per mm³ of hydrogen if pressured compared to less pressured .

    If we are assuming normal atmospheric pressure, then knowing that we have one gram of hydrogen will already give us the volume.

    Unless you have anything else to add, I think I have all I need to do the math. Should I start?
    Yea you can try , I'll be interested to see what you come up with .
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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #153 on: 03/04/2019 00:15:23 »
    Quote from: Thebox on 02/04/2019 23:16:37
    Yea you can try , I'll be interested to see what you come up with .

    I can't directly copy the equation text as you've written it (is it an image file?), but this should be an equivalent expression: (uE3)/(V/t)

    "E" equals "hf3", which is the Planck constant multiplied by photon frequency. I'll use a very powerful photon in the form of a gamma ray (1019 hertz). 1019 cubed is 1057. So "E" equals (6.62607015×10−34 joule-seconds) x (1057 hertz). Multiply that out and you get 6.62607015 x 1023.

    One gram of hydrogen is equal to 0.49611 moles of hydrogen, which occupies 11.1129 liters of volume (0.0111129 cubic meters). So now I have the needed values:

    Combustion energy =  (uE3)/(V/t)
    = ((0)*((6.62607015 x 1023)3))/(0.0111129/10)
    = ((0)*((2.909163 x 1071)))/(0.00111129)
    = (0)/(0.00111129)
    = 0 joules

    Okay, so we've run into a problem. By making "u" equal to zero, the equation predicts that no energy is released at all by hydrogen burning. However, there is a way around this. Maybe instead of net charge you meant gross charge instead? That way, instead of subtracting the charge on the electrons from the charge on the protons and getting zero, you add them together and get a finite number (6.4087064 x 10[/sup]-19[/sup] coulombs of charge, to be precise). Here's what happens if I do that instead:

    Combustion energy =  (uE3)/(V/t)
    = ((6.4087064 x 10-19)*((6.62607015 x 1023)3))/(0.0111129/10)
    = ((6.4087064 x 10-19)*((2.909163 x 1071)))/(0.00111129)
    = (1.864397 x 1053)/(0.00111129)
    = 1.677687 x 1056 joules

    How about that? Does that look good?
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #154 on: 03/04/2019 01:08:13 »
    Quote from: Kryptid on 03/04/2019 00:15:23
    Quote from: Thebox on 02/04/2019 23:16:37
    Yea you can try , I'll be interested to see what you come up with .

    I can't directly copy the equation text as you've written it (is it an image file?), but this should be an equivalent expression: (uE3)/(V/t)

    "E" equals "hf3", which is the Planck constant multiplied by photon frequency. I'll use a very powerful photon in the form of a gamma ray (1019 hertz). 1019 cubed is 1057. So "E" equals (6.62607015×10−34 joule-seconds) x (1057 hertz). Multiply that out and you get 6.62607015 x 1023.

    One gram of hydrogen is equal to 0.49611 moles of hydrogen, which occupies 11.1129 liters of volume (0.0111129 cubic meters). So now I have the needed values:

    Combustion energy =  (uE3)/(V/t)
    = ((0)*((6.62607015 x 1023)3))/(0.0111129/10)
    = ((0)*((2.909163 x 1071)))/(0.00111129)
    = (0)/(0.00111129)
    = 0 joules

    Okay, so we've run into a problem. By making "u" equal to zero, the equation predicts that no energy is released at all by hydrogen burning. However, there is a way around this. Maybe instead of net charge you meant gross charge instead? That way, instead of subtracting the charge on the electrons from the charge on the protons and getting zero, you add them together and get a finite number (6.4087064 x 10[/sup]-19[/sup] coulombs of charge, to be precise). Here's what happens if I do that instead:

    Combustion energy =  (uE3)/(V/t)
    = ((6.4087064 x 10-19)*((6.62607015 x 1023)3))/(0.0111129/10)
    = ((6.4087064 x 10-19)*((2.909163 x 1071)))/(0.00111129)
    = (1.864397 x 1053)/(0.00111129)
    = 1.677687 x 1056 joules

    How about that? Does that look good?
    Wow , yes it looks good , I have no idea what it means lol , that's why I have a simple equation . Does it work ?

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    Offline Kryptid

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  • Re: 5d interwoven model and tensor force .
    « Reply #155 on: 03/04/2019 05:33:20 »
    Quote from: Thebox on 03/04/2019 01:08:13
    Wow , yes it looks good , I have no idea what it means lol , that's why I have a simple equation . Does it work ?

    The enthalpy of combustion of hydrogen is 141,580 joules per gram according to https://www.engineeringtoolbox.com/standard-heat-of-combustion-energy-content-d_1987.html

    141,580 joules per gram is nowhere remotely the same as 1.677687 x 1056 joules per gram.
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    Offline Bored chemist

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  • Re: 5d interwoven model and tensor force .
    « Reply #156 on: 03/04/2019 07:26:37 »
    Quote from: Thebox on 03/04/2019 01:08:13
    I have a simple equation . Does it work ?
    No, of course not.
    That's what we have said all along.
    Your calculation is nonsense.
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #157 on: 03/04/2019 13:44:59 »
    Quote from: Kryptid on 03/04/2019 05:33:20
    Quote from: Thebox on 03/04/2019 01:08:13
    Wow , yes it looks good , I have no idea what it means lol , that's why I have a simple equation . Does it work ?

    The enthalpy of combustion of hydrogen is 141,580 joules per gram according to https://www.engineeringtoolbox.com/standard-heat-of-combustion-energy-content-d_1987.html

    141,580 joules per gram is nowhere remotely the same as 1.677687 x 1056 joules per gram.
    Perhaps the answer shouldn't be in joules , how do they derive their equation ?  Are they doing it correctly  ?

    nX + mO2  →  xCO2 (g) + yH2O (l) + zZ + heat of combustion

    HUh what's that suppose to mean ?

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  • Re: 5d interwoven model and tensor force .
    « Reply #158 on: 03/04/2019 13:45:35 »
    Quote from: Bored chemist on 03/04/2019 07:26:37
    Quote from: Thebox on 03/04/2019 01:08:13
    I have a simple equation . Does it work ?
    No, of course not.
    That's what we have said all along.
    Your calculation is nonsense.
    Nope , my equation works , values are just final touches .

    Look at this way

    A glass full of water

    u=1/2 ltr
    E³ = +1/2ltr

    Output overflow 1/2 ltr

    0ab0f63b841f77909b211b3791778aca.gif=1/2 ltr

    Combustion energy =  (uE3)/(V/t)
    = ((0)*((6.62607015 x 1023)3))/(0.0111129/10)
    = ((0)*((2.909163 x 1071)))/(0.00111129)
    = (0)/(0.00111129)
    = 0 joules

    Would be correct , the energy released is kinetics .

    Antoine - nothing is lost and nothing is gained .
    The hydrogen atom loses no energy in the process of combustion .
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    guest39538

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  • Re: 5d interwoven model and tensor force .
    « Reply #159 on: 03/04/2019 14:09:04 »
    The equation tells you that

    Δu = ΔE³ = ΔkE = Δ T / t


    u / t is a constant and the idol measure , u always returns to u , nothing lost and nothing gained .

    Natural temperature 0 .

    u = m

    m+m = m2

    m*m=m³

    m/V= <m

    I won't add a big bang equation .

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